Answer:
1/(m^4*n^2
Step-by-step explanation:
The given expression is
(m^2*n^-3)/(m^6*n^-1)
Tyrone's approach.
Raising the expression to the 3rd power will not help. It will make the expression more complicated.
Alisha's approach.
(m^2*n^-2)/(m^6*n^-1)
= m^(2-6)*n^(-3+1)
= m^-4*n^-2
= 1/(m^4*n^2)
Alisha's approach will simplify the expression to 1/(m^4*n^2
<span><span><span><span>g<span>t2</span></span>2</span>=2g</span><span><span><span>g<span>t2</span></span>2</span>=2g</span></span><span> or 19.9m.</span>
The answer is
96%.
Explanation:
It is generally presumed that the scores are normally distributed.
1) You are given how many standard deviations from the mean Jeremy's score is. This is exactly the definition of the
z-score. Therefore z = 1.75
2) Look at a left-tail z-table in order to find the area of the normal curve on the left of your z-score (see picture attached). A = 0.9599
3) Multiply the area by 100 in order to find the
percentile:
<span>0.9599 </span>× 100 = 95.99
Therefore, 95.99% of the students scored less than Jeremy.
Hence, the answer is
96%.
Answer:
0.4970
Step-by-step explanation:
I might be wrong