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Firlakuza [10]
2 years ago
15

What is the fraction answer

Mathematics
1 answer:
Ket [755]2 years ago
5 0

Answer:

1230 divided by 16 equals 76 seven eighth's

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Baby Amelia's parents measure her height every month.
jonny [76]

The statement H(30) = H(25) + 5 means that, "when Amelia was 30 months old, she was 5 centimeters taller than when she was 25 months old"

<h3><u>Solution:</u></h3>

Given that,

Baby Amelia's parents measure her height every month

It is given that H(t) models Amelia's height (in centimeters) when she was "t" months old

Given statement is H(30) = H(25) + 5

So, we can say that H(30) = Amelia's height when she was 30 months old

H(25) = Amelia's height when she was 25 months old

So H(30) = H(25) + 5 means that,

Height of Amelia when she was 30 months old is 5 centimeter more than Amelia height when she was 25 years old

Or we can say that,

When Amelia was 30 months old, she was 5 centimeters taller than when she was 25 months old

7 0
3 years ago
5 Divided by 35.15?<br> Sorry if I spam a lot of questions it’s my final exam for school.
Orlov [11]
ANSWER: 0.142247510668563
5 0
2 years ago
Read 2 more answers
What is the slope of the line on the graph?
Lelechka [254]

Answer:

5,-1,-7

Step-by-step explanation:

7 0
3 years ago
Which expression is equivalent to (2^1/2 2^3/4)^2
dimaraw [331]

Answer:

\sqrt{2^5}

Step-by-step explanation:

2^{1/2} × 2^{3/4} = 2^{5/4}

(2^{5/4})² = 2^{5/2} = \sqrt{2^5}

6 0
3 years ago
Read 2 more answers
If p(a | b) = 0.4, p(b) = 0.8, and p(a) = 0.5, are the events a and b independent?
pashok25 [27]

The events A and B are not independent.

Given that,

                  P(A|B) = 0.4

                  P(A) = 0.5

                  P(B) = 0.8

Two events A and B are said to be independent, if P(A∩B) = P(A) P(B)

We have, P(A|B) = P(A∩B)/P(B)

Therefore, P(A∩B) = P(A|B) P(B) = 0.4 x 0.8 = 0.32

Now P(A) P(B) = 0.5 x 0.8 = 0.4

So P(A∩B) ≠ P(A)P(B)

Therefore, the events A and B are not independent.

Learn more about independent events at brainly.com/question/22881926

#SPJ4

7 0
1 year ago
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