Correct Answer:
Option D (12, -5)
In Quadrant IV, the x-component of the point is positive and the y-component is negative. From the given points, option D contains the point with a positive x-component i.e.12 and negative y-component i.e -5. Therefore, this point lies in Quadrant IV.
Answer:
It shifted 6 units down
Step-by-step explanation:
Do the graph normally without the k and compare them side by side.
Hello! here are the basic rules that you need to know to solve these problems:
a diameter is 2 × the radius
the circumference rule is 2×π×radius
I will solve the first question to show how to format.
1: 5/2=2.5
2×2.5×π=5×π=15.7
<span>Hello there, i think the answer is 15=3*5
(Please leave a thanks if this IS the right answer! Thanks ;)
What times 3 = 15?
x*3=15
X=5</span>
