Answer:
in 4/5 fraction of the game they scored two or more runs.
Probability=number of specific outcomes / total possible outcomes
P(g)=12/(12+8)
P(g)=12/20
P(g)=3/5
9+3=12
30+20=50
300+100=400
Then add.
12+50+400=462
<span>So 339+123=462</span>
The possible different outcomes are: c. 6 outcomes.
you can only count "e" once because even though it is in the bag twice, drawing it a second time would be the same outcame.
hope this help
