Question

Find the horizontal [A] and vertical [B] components of the given vector. Round to four places.

Answer 1

Answer:

• The equation of the horizontal component is:

$v_x=v\:cos\:\theta \:$

   $=-10.7294$

• The vertical component will be:

$v_y=v\:sin\:\theta \:\:$

    $=-16.5218$

   

Step-by-step explanation:

Let 'v' be the vector

The equation of the horizontal component is:

$v_x=v\:cos\:\theta \:$

The equation of the vertical component is:

$v_y=v\:sin\:\theta \:\:$

• The magnitude of a vector 'v' is expressed as 'v'.

As

• Magnitude = v = 19.7

• Ф = 237°

The horizontal component will be:

$v_x=v\:cos\:\theta \:$

    $=\left(19.7\right)\cos \left(237^{\circ \:}\right)$

     $=-10.7294$

The vertical component will be:

$v_y=v\:sin\:\theta \:\:$

    $=19.7\sin \:\left(237^{\circ \:\:}\right)$

    $=-16.5218$