I think it is 5%, hope it help
R = m - v + 2, where r = faces, v = vertices, and m = edges
r = 28 - 13 + 2
r = 15 + 2
r = 17, so the first answer is correct.
7. The surface area of a cone is A = pi*r*sqrt(r^2 + H^2)
A = pi*(7)(sqrt(49 + 1849)
A = pi*(7)(43.57)
A = pi*305 = 959 m^2, so the first answer is correct.
13. The volume of the slab is V = HLW
V = (5 yards)(5 yards)(1/12 yards)
V = 25/12 cubic yards
So it costs $46.00*(25/12) = $95.83 of total concrete. The third answer is correct.
21. First, find the volume of the rectangular prism. V = HLW
V = (15 cm)(5 cm)(7 cm)
V = 525 cm^3
Next, find the volume of the pyramid. V = 1/3(BH), where H is the height of the pyramid and B is the area of the base of the pyramid. Note that B = (15 cm)(5 cm) = 75 cm^2
V = (1/3)(75 cm^2)(13 cm)
V = 325 cm^3
Add the two volumes together, the total volume is 850 cm^3. The fourth answer is correct.
22. The volume of a square pyramid is V = 1/3(S^2)(H), where S is the side length and H is the height.
V = (1/3)(20^2 in^2)(21 in)
V = 2800 in^3
Now that we know the volume of this pyramid, and that both pyramids have equal volume, we plugin our V to the equation for the volume.
2800 = (1/3)(84)(S^2)
2800 = 28S^2
100 = S^2
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10 in = S, so we have a side length of 10 in, and the first answer is correct. </span>
87 the to you do why try ice
Answer:
The answer is below
Step-by-step explanation:
∠EFG and ∠GFH are a linear pair, m∠EFG = 3n+ 21, and m∠GFH = 2n + 34. What are m∠EFG and m∠GFH?
Solution:
Two angles are said to form a linear pair if they share a base. Linear pair angles are adjacent angles formed along a line as a result of the intersection of two lines. Linear pairs are always supplementary (that is they add up to 180°).
m∠EFG = 3n + 21, m∠GFH = 2n + 34. Both angles form linear pairs, hence:
m∠EFG + m∠GFH = 180°
3n + 21 + (2n + 34) = 180
3n + 2n + 21 + 34 = 180
5n + 55 = 180
5n = 125
n = 25
Therefore, m∠EFG = 3(25) + 21 = 96°, m∠GFH = 2(25) + 34 = 84°
If two sides of a right triangle are x and y, the hypotenuse, h is:
h^2=x^2+y^2, in this case x and y are 39 and 52 respectively so:
h^2=39^2+52^2
h^2=1521+2704
h^2=4225
h=√4225
h=65 in
So the hypotenuse is 65 inches.
