All categories

3 years ago

Need help???!!!!!!!!!!!!!!!

Mathematics

2 answers:

solong [7]3 years ago

5 0

Answer:

Step-by-step explanation:

because it makes sense

In-s [12.5K]3 years ago

4 0

It’s e bae :) sorry im late!! Good luck

You might be interested in

) Use the Laplace transform to solve the following initial value problem: y′′−6y′+9y=0y(0)=4,y′(0)=2 Using Y for the Laplace tra

artcher [175]

Answer:

$y(t)=2e^{3t}(2-5t)$

Step-by-step explanation:

Let Y(s) be the Laplace transform Y=L{y(t)} of y(t)

Applying the Laplace transform to both sides of the differential equation and using the linearity of the transform, we get

L{y'' - 6y' + 9y} = L{0} = 0

(*) L{y''} - 6L{y'} + 9L{y} = 0 ; y(0)=4, y′(0)=2

Using the theorem of the Laplace transform for derivatives, we know that:

$\large\bf L\left\{y''\right\}=s^2Y(s)-sy(0)-y'(0)\\\\L\left\{y'\right\}=sY(s)-y(0)$

Replacing the initial values y(0)=4, y′(0)=2 we obtain

$\large\bf L\left\{y''\right\}=s^2Y(s)-4s-2\\\\L\left\{y'\right\}=sY(s)-4$

and our differential equation (*) gets transformed in the algebraic equation

$\large\bf s^2Y(s)-4s-2-6(sY(s)-4)+9Y(s)=0$

Solving for Y(s) we get

$\large\bf s^2Y(s)-4s-2-6(sY(s)-4)+9Y(s)=0\Rightarrow (s^2-6s+9)Y(s)-4s+22=0\Rightarrow\\\\\Rightarrow Y(s)=\frac{4s-22}{s^2-6s+9}$

Now, we brake down the rational expression of Y(s) into partial fractions

$\large\bf \frac{4s-22}{s^2-6s+9}=\frac{4s-22}{(s-3)^2}=\frac{A}{s-3}+\frac{B}{(s-3)^2}$

The numerator of the addition at the right must be equal to 4s-22, so

A(s - 3) + B = 4s - 22

As - 3A + B = 4s - 22

we deduct from here

A = 4 and -3A + B = -22, so

A = 4 and B = -22 + 12 = -10

It means that

$\large\bf \frac{4s-22}{s^2-6s+9}=\frac{4}{s-3}-\frac{10}{(s-3)^2}$

and

$\large\bf Y(s)=\frac{4}{s-3}-\frac{10}{(s-3)^2}$

By taking the inverse Laplace transform on both sides and using the linearity of the inverse:

$\large\bf y(t)=L^{-1}\left\{Y(s)\right\}=4L^{-1}\left\{\frac{1}{s-3}\right\}-10L^{-1}\left\{\frac{1}{(s-3)^2}\right\}$

we know that

$\large\bf L^{-1}\left\{\frac{1}{s-3}\right\}=e^{3t}$

and for the first translation property of the inverse Laplace transform

$\large\bf L^{-1}\left\{\frac{1}{(s-3)^2}\right\}=e^{3t}L^{-1}\left\{\frac{1}{s^2}\right\}=e^{3t}t=te^{3t}$

and the solution of our differential equation is

$\large\bf y(t)=L^{-1}\left\{Y(s)\right\}=4L^{-1}\left\{\frac{1}{s-3}\right\}-10L^{-1}\left\{\frac{1}{(s-3)^2}\right\}=\\\\4e^{3t}-10te^{3t}=2e^{3t}(2-5t)\\\\\boxed{y(t)=2e^{3t}(2-5t)}$

5 0

3 years ago

Perform the indicated operation. (-50) ÷ (-2) 48 -48 -25 25

mezya [45]

Answer:

Step-by-step explanation:

Remember that multiplication and division will result in a positive number if no or two negative signs are present. So here, you ignore the negative signs.

All you really have to do is divide 50 by 2, which results in 25.

7 0

3 years ago

Read 2 more answers

What is -4x with an exponent of zero?

Anton [14]

Answer

-4

Step-by-step explanation:

x^0 = 1

so -4x^0

= -4

7 0

3 years ago

Read 2 more answers

A carpenter has wood planks that are 4 yards, 8 yards, 7 yards, and 3 yards long. what is the mad of these measurements

noname [10]

Answer:

Step-by-step explanation:

what you have to do to find that out is add them all togeather the divide that whole by the amount of numbers you were adding so in this case it would be 3 so you would add 8,7, and 3 to get 18 then divide that by 3 to get 6.

hope this helps

pls mark brainliest

8 0

2 years ago

What is the value of x? Do not round the answer.

inysia [295]

Answer:

Step-by-step explanation:

By definition, CD is an angle bisector. What that does is creates proportionality between the sides of each respective triangle. Here's the proportion:

$\frac{4}{3} =\frac{7.5}{x}$

Cross multiply to get 4x = 22.5 and

x = 5.625

6 0

2 years ago