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kotykmax [81]
3 years ago
11

Need help???!!!!!!!!!!!!!!!

Mathematics
2 answers:
solong [7]3 years ago
5 0

Answer:

E

Step-by-step explanation:

because it makes sense

In-s [12.5K]3 years ago
4 0
It’s e bae :) sorry im late!! Good luck
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A binomial probability experiment is conducted with the given parameters. Compute the probability of x successes in the n indepe
-Dominant- [34]

Answer: 0.0031

Step-by-step explanation:

Binomial distribution formula :-

P(x)=^nC_xp^x(1-p)^{n-x}, where P(x) is the probability of x successes in the n independent trials of the experiment and p is the probability of success.

Given : A binomial probability experiment is conducted with the given parameters.

n=9,\ p=0.8,\ x\leq3

Now, P(x\leq3)=P(3)+P(2)+P(1)+P(0)

=^9C_3(0.8)^3(1-0.8)^{9-3}+^9C_2(0.8)^2(1-0.8)^{9-2}+^9C_1(0.8)^1(1-0.8)^{9-1}+^9C_0(0.8)^0(1-0.8)^9\\\\=\dfrac{9!}{3!6!}(0.8)^3(0.2)^6+\dfrac{9!}{2!7!}(0.8)^2(0.2)^7+\dfrac{9!}{1!8!}(0.8)(0.2)^8+\dfrac{9!}{0!9!}(0.2)^9=0.003066368\approx0.0031

Hence,  P(x\leq3)=0.0031

8 0
3 years ago
Please help !!
S_A_V [24]

Answer:

The top right graph.

Step-by-step explanation:

5 0
3 years ago
Escribe una expresión algebraica para la palabra frase: el producto de 636 y un número w
diamong [38]

Answer:

636w

Step-by-step explanation:

producto = ×

636 \times w\\\\= 636w

5 0
2 years ago
Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating
natulia [17]

Answer:

V=25088π vu

Step-by-step explanation:

Because the curves are a function of "y" it is decided to take the axis of rotation as y

, according to the graph 1 the cutoff points of f(y)₁ and f(y)₂ are ±2

f(y)₁ = 7y²-28;  f(y)₂=28-7y²

y=0;   x=28-0 ⇒ x=28

x=0;   0 = 7y²-28 ⇒ 7y²=28 ⇒ y²= 28/7 =4 ⇒ y=√4 =±2

Knowing that the volume of a solid of revolution  V=πR²h, where R²=(r₁-r₂) and h=dy then:

dV=π(7y²-28-(28-7y²))²dy ⇒dV=π(7y²-28-28+7y²)²dy = 4π(7y²-28)²dy

dV=4π(49y⁴-392y²+784)dy integrating on both sides

∫dV=4π∫(49y⁴-392y²+784)dy ⇒ solving  ∫(49y⁴-392y²+784)dy

49∫y⁴dy-392∫y²dy+784∫dy =

V=4π( 49\frac{y^{5} }{5}-392\frac{y^{3}}{3}+784y ) evaluated -2≤y≤2, or 2(0≤y≤2), also

V=8\pi(49\frac{2^{5} }{5}-392\frac{2^{3} }{3}+784.2)  ⇒ V=25088π vu

8 0
3 years ago
Please help!<br> Solve for y.<br><br> 2x+5y=4<br><br> Solve for t.<br> A=p+prt
Elan Coil [88]
1. y=(4-2x)/5
2. t=(A-p)/pr
OR
t=A/pr - 1/r
4 0
3 years ago
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