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hoa [83]
3 years ago
11

Ted researched the price of airline tickets and discovered a correlation between the price of a ticket and the number of miles t

raveled. After recording his data on a scatter plot, he determined the equation for the line of best fit is y = 300 + 0.45x. What does 0.45 represent in the equation? A) the lowest ticket price B) the number of miles traveled C) the expected change in the price of multiple tickets Eliminate D) the expected change in price of the ticket for each mile traveled
Mathematics
2 answers:
Nookie1986 [14]3 years ago
7 0
D) the expected change in price <span>of the ticket for each mile traveled
Because it is a coloration between the two </span>
andriy [413]3 years ago
4 0
D) the expected change in price <span>of the ticket for each mile traveled
Because it is a coloration between the two </span><span />
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I need help plz plz plz
Katena32 [7]
Your answer to this question is B
3 0
3 years ago
If the scale factor of a dilation is 4/3 the image will be a reduction of the pre-image, because 4/3 is a fraction less than one
Law Incorporation [45]
True and sorry if I’m incorrect
6 0
2 years ago
Helen had Php7500 for shopping money. When she got home, she had Php132.75 in her pocket. How much did she spend for shopping?
Nataly_w [17]

Answer:

Step-by-step explanation:

Helen had Php7500 for shopping money

she had Php132.75 in her pocket

she spend= 7500.00-132.75

=7367.25answer

4 0
3 years ago
Make x the subject of y=alog(5x)
Bond [772]

Answer:

x = 0.2(10^y/a).

Step-by-step explanation:

y = alog(5x)

y = log(5x)^a)   By the definition of a log:

(5x)^a  = 10^y

5x = (10^y) ^ 1/a

x = 0.2(10^y/a)

4 0
3 years ago
If (ax+2)(bx+7)=15x2+cx+14 for all values of x, and a+b=8, what are the 2 possible values fo c
dolphi86 [110]

Given:

(ax+2)(bx+7)=15x^2+cx+14

And

a+b=8

Required:

To find the two possible values of c.

Explanation:

Consider

\begin{gathered} (ax+2)(bx+7)=15x^2+cx+14 \\ abx^2+7ax+2bx+14=15x^2+cx+14 \end{gathered}

So

\begin{gathered} ab=15-----(1) \\ 7a+2b=c \end{gathered}

And also given

a+b=8---(2)

Now from (1) and (2), we get

\begin{gathered} a+\frac{15}{a}=8 \\  \\ a^2+15=8a \\  \\ a^2-8a+15=0 \end{gathered}a=3,5

Now put a in (1) we get

\begin{gathered} (3)b=15 \\ b=\frac{15}{3} \\ b=5 \\ OR \\ b=\frac{15}{5} \\ b=3 \end{gathered}

We can interpret that either of a or b are equal to 3 or 5.

When a=3 and b=5, we have

\begin{gathered} c=7(3)+2(5) \\ =21+10 \\ =31 \end{gathered}

When a=5 and b=3, we have

\begin{gathered} c=7(5)+2(3) \\ =35+6 \\ =41 \end{gathered}

Final Answer:

The option D is correct.

31 and 41

8 0
1 year ago
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