Area of the parabolic region = Integral of [a^2 - x^2 ]dx | from - a to a =
(a^2)x - (x^3)/3 | from - a to a = (a^2)(a) - (a^3)/3 - (a^2)(-a) + (-a^3)/3 =
= 2a^3 - 2(a^3)/3 = [4/3](a^3)
Area of the triangle = [1/2]base*height = [1/2](2a)(a)^2 = <span>a^3
ratio area of the triangle / area of the parabolic region = a^3 / {[4/3](a^3)} =
Limit of </span><span><span>a^3 / {[4/3](a^3)} </span>as a -> 0 = 1 /(4/3) = 4/3
</span>
Answer:
A rectangle is defined by its length = L, and its width = W.
So the perimeter of the of the rectangle can be written as:
Perimeter = 2*L + 2*W.
In this case, we want to leave the perimeter fixed, so we have:
24ft = 2*L + 2*W.
Now, we do not have any other restrictions, so to know the different dimensions now we can write this as a function, by isolating one of the variables.
2*L = 24ft - 2*W
L = 12ft - W.
or:
L(W) = 12ft - W.
Such that:
W must be greater than zero (because we can not have negative or zero width).
And W must be smaller than 12ft (because in that case we would have zero or negative length)
Then the possible different dimensions are given by:
L(W) = 12ft - W
0ft < W < 12ft.
Answer:
AZ=8
AB=16
Step-by-step explanation:
3x-4=2x
-4=-x
x=4
3x-4
3(4) - 4
12-4
8
Answer:
Yellow is the answer
Step-by-step explanation:
