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3 years ago

Find the value of X,Y and Z

Mathematics

1 answer:

Alex3 years ago

3 0

Answer:

If sin y = sin 35, y≠35, what is the value of y? 2. If cos y = cos z = - cos 35, y≠z≠35, what are the values of y and z? 3. If sin y = sin x and x<90, y≠x, what is the value of y in terms of x? 4. If sin y = sin z = -sin x and x<90, y≠z≠x, what are the values of y and z in terms of x? 5. If cos y = cos x and x<90, y≠x, what are the value of y and z in terms of x? 6. If cos y = cos z = - cos x and x<90, y≠z≠x, what are the values of y and z in terms of x?

Step-by-step explanation:

Because I know

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The brand manager for a brand toothpaste must plan a campaign designed to increase brand recognition. He wants to first determin

bulgar [2K]

We need to find out how many adults must the brand manager survey in order to be 90% confident that his estimate is within five percentage points of the true population percentage.

From the given data we know that our confidence level is 90%. From Standard Normal Table we know that the critical level at 90% confidence level is 1.645. In other words, $Z_{Critical}=1.645$ .

We also know that E=5% or E=0.05

Also, since, $\hat{p}$ is not given, we will assume that $\hat{p}$ =0.5. This is because, the formula that we use will have $\hat{p}(1-\hat{p})$ in the expression and that will be maximum only when $\hat{p}$ =0.5. (For any other value of $\hat{p}$ , we will get a value less than 0.25. For example if, $\hat{p}$ is 0.4, then $1-\hat{p}=0.6$ and thus, $\hat{p}(1-\hat{p})=0.24$ .).

We will now use the formula

$n=(\frac{Z_{Critical}}{E})^2\hat{p}(1-\hat{p})$

We will now substitute all the data that we have and we will get

$n=(\frac{1.645}{0.05})^2\times0.5(1-0.5)$

$n=(32.9)^2\times0.25$

$n=270.6025$

which can approximated to n=271.

So, the brand manager needs a sample size of 271

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3 years ago

The sum is 2 One number is twice the other one.

Scorpion4ik [409]

Answer:

The smaller number is 0.6666... repeating, and the larger number is 1.3333... repeating.

Step-by-step explanation:

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3 years ago

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tatyana61 [14]

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3 years ago

Read 2 more answers

A farmer has both pigs and chickens on his farm there are 78 fee and 27 heads how many pigs and how many chickens are there

Andre45 [30]

Assuming health non-mutated animals:
$Feet = 4*Pigs + 2*Chickens$
$Heads = Pigs + Chickens$

By back substitution:
$78 = 4*(27-Chickens) + 2*Chickens$
$78 = 108 -2*Chickens$
$-30 = -2*Chickens$
$Chickens= 15$

Then:
$27 = Pigs + 15$
$Pigs = 12$

To check:
$Feet = 4*Pigs + 2*Chickens$
$78 = 4*12 + 2*15$
$78 = 48 + 30$
$78 = 78$ CHECKS

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4 years ago

Trigonometry help!! - double angle formulae

ivolga24 [154]

Answer:

The two rules we need to use are:

Sin(a + b) = sin(a)*cos(b) + sin(b)*cos(a)

cos(a + b) = cos(a)*cos(b) - sin(a)*sin(b)

And we also know that:

sin^2(a) + cos^2(a) = 1

To solve the relations, we start with the left side and try to construct the right side.

a) Sin(3*A) = sin (2*A + A) = sin(2*A)*cos(A) + sin(A)*cos(2*A)

sin(A + A)*cos(A) + sin(A)*cos(A + A)

(sin(A)*cos(A) + sin(A)*cos(A))*cos(A) + sin(A)*(cos(A)*cos(A) - sin(A)*sin(A))

sin(A)*cos^2(A) + sin(A)*cos^2(A) + sin(A)*cos^2(A) - sin^3(A)

3*sin(A)*cos^2(A) - sin(A)*sin^2(A)

sin(A)*(3*cos^2(A) - sin^2(A))

Now we can add and subtract 4*sin^3(A)

sin(A)*(3*cos^2(A) - sin^2(A)) + 4*sin^3(A) - 4*sin^3(A)

sin(A)*(3*cos^2(A) + 3*sin^2(A)) - 4*sin^3(A)

sin(A)*3*(cos^2(A) + sin^2(A)) - 4*sin^3(A)

3*sin(A) - 4*sin^3(A)

b) Here we do the same as before:

cos(3*A) = 4*cos^3(A) - 3*cos(A)

We start with:

Cos(2*A + A) = cos(2*A)*cos(A) - sin(2*A)*sin(A)

= cos(A + A)*cos(A) - sin(A + A)*sin(A)

= (cos(A)*cos(A) - sin(A)*sin(A))*cos(A) - ( sin(A)*cos(A) + sin(A)*cos(A))*sin(A)

= (cos^2(A) - sin^2(A))*cos(A) - sin^2(A)*cos(A) - sin^2(A)*cos(A)

= cos^3(A) - 3*sin^2(A)*cos(A)

= cos(A)*(cos^2(A) - 3*sin^2(A))

now we subtract and add 4*cos^3(A)

= cos(A)*(cos^2(A) - 3*sin^2(A)) + 4*cos^3(A) - 4*cos^3(A)

= cos(A)*(-3*cos^2(A) - 3*sin^2(A)) + 4*cos^3(A)

= cos(A)*(-3)*(cos^2(A) + sin^2(A)) + 4*cos^3(A)

= -3*cos(A) + 4*cos^3(A)

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3 years ago