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Soloha48 [4]
3 years ago
7

The ratio of cats to dogs is 3 : 7.

Mathematics
1 answer:
JulsSmile [24]3 years ago
6 0

Given:

The ratio of cats to dogs is 3:7.

12 dogs escaped and the ratio is now 3 : 4.

To find:

The total number of animal at the beginning.

Solution:

Let the number of cats and dogs at the beginning are 3x and 7x respectively.

12 dogs escaped. So, the remaining number of dogs is (7x-12).

New ratio of cats and dogs is 3:4.

\dfrac{3x}{7x-12}=\dfrac{3}{4}

4(3x)=3(7x-12)

12x=21x-36

12x-21x=-36

-9x=-36

Divide both sides by -9.

\dfrac{-9x}{-9}=\dfrac{-36}{-9}

x=4

Now, the total number of animals at the beginning is

Total=3x+7x

Total=10x

Total=10(4)

Total=40

Therefore, the total number of animals at the beginning is 40.

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When 3 is subtracted from one third of a number less than 6. Which inequality and solution represents this sitution?
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Answer:

1/3(n) - 3 < 6; n < 27

Step-by-step explanation:

" 3 subtracted from one third of a number"

= 1/3(n) - 3

given that this is less than 6:

1/3(n) - 3 < 6

1/3(n) < 6 +3

1/3(n) < 9

n < 27

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I think its 24 because 6*2 equals 12 but you cant multiply 8 by anything to get 12
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Please help me pleaseeeee!!​
mafiozo [28]

Answer:

The median is 40. The least number of smartphones distributed is 34. Finally, the third quartile is 48. Hope this helps!

Step-by-step explanation:

4 0
2 years ago
Graph the line with slope -2 passing through the point (4, 1)
Scrat [10]

Answer:

Use points (4,1) and (3,-1)

Step-by-step explanation:

Let's say the other coordinates are (x,y).

Then, we know (1-y)/(4-x)=2. So if y is -1, and x is 3, then we get:

[1-(-1)]/(4-3)=2/1=2

So draw the two points, (4,1) and (3,-1) on a coordinate plane, and use a ruler to make a line that goes through both the points.

4 0
2 years ago
NEED HELP ASAP
Jobisdone [24]

ANSWER: A. 46

 

 

SOLUTION

 

Given that Q is equidistant from the sides of TSR

m∠TSQ = m ∠QSR

 

To solve for x

m∠TSQ = 3x + 2

m ∠QSR = 8x – 33

 

Since m∠TSQ = m ∠QSR

3x + 2 = 8x – 33

 

Add 33 to both sides

3x + 2 + 33 = 8x – 33 + 33

3x + 35 = 8x

8x = 3x + 35

 

Subtract 3x from both sides

8x – 3x = 3x – 3x + 35

5x = 35

 

Divide both sides by 5

x = 7

 

Since m∠TSQ = 3x + 2, and x = 7

m∠TSQ = (3*7) + 2

m∠TSQ = 21 + 2

m∠TSQ = 23

 

To solve for RST

Given that Q is equidistant from the sides of RST

m∠RST = m∠TSQ + m ∠QSR

Since m∠TSQ = m ∠QSR

m∠RST = 2m∠TSQ = 2m ∠QSR

 

Ginen, m∠RST = 2m∠TSQ

m∠TSQ = 23

m∠RST = 2(23)

m∠RST = 46

7 0
2 years ago
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