Answer:
a. 61.92 in²
b. 21.396 ≈ 21.4%
c. $4.71
Step-by-step explanation:
a. Amount of waste = area of rectangular piece of stock - area of two identical circles cut out
Area of rectangular piece of stock = 24 in × 12 in = 288 in²
Area of the two circles = 2(πr²)
Use 3.14 as π
radius = ½*12 = 6
Area of two circles = 2(3.14*6²) = 226.08 in²
Amount of waste = 288 - 226.08 = 61.92 in²
b. % of the original stock wasted = amount of waste ÷ original stock × 100
= 61.92/288 × 100 = 6,162/288 = 21.396 ≈ 21.4%
c. 288 in² of the piece of stock costs $12.00,
Each cut-out circle of 113.04 in² (226.08/2) will cost = (12*113.04)/288
= 1,356.48/288 = $4.71.
(1 gal, 2 qt, 3 pt) +
(1 gal, 3 qt, 7 pt) +
(1 gal, 3 qt, 3 pt)
= (3 gal, 8 qt, 13 pt)
= (3 gal, 14 qt, 1 pt)
= (6 gal, 2 qt, 1 pt)
The total volume of punch is 6 gallons, 2 quarts, 1 pint, or 6 5/8 gallons.
Answer:
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Answer:
see below
Step-by-step explanation:
3x^2 + 17x +10 =0
(3x+ ) ( x+ ) =0
We need to factor 10 = 2*5 or 1*10
They are positive since we have all positive terms
3*5 = 15+2 = 17
The 5 needs to multiply the 3 so it goes on the outside
(3x+ ) ( x+ 5 ) =0
That leaves the 2 on the inside
(3x+ 2 ) ( x+ 5 ) =0
Using the zero product property
3x+2 =0 x+5=0
3x = -2 x=-5
x = -2/3 x = -5
