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taurus [48]
3 years ago
14

Figure 1 is dilated to get Figure 2.

Mathematics
2 answers:
VMariaS [17]3 years ago
8 0

Answer:

2.25

Step-by-step explanation:


Anastasy [175]3 years ago
3 0
Answer: 2.25

Divide the corresponding values. You'll divide figure 2's length over figure 1's corresponding length. So 18/8 = 2.25

This means each side of figure 2 is 2.25 times larger than the corresponding side for figure 1
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Which of these strategies would eliminate a variable in the system of equations? \begin{cases} 6x + 5y = 1 \\\\ 6x - 5y = 7 \end
frez [133]

Answer:

Option A and B are correct

Step-by-step explanation:

We have to add here

6x+5y=1.

6x-5y=7

sow e will get 12x=8 , x=8/12=2/3

Option A  is correct.

If We substract bottom from furst then

6x+5y=1

-6x+5y=-7

10y=-6

y=-6/10=-3/5

we put y=-3/5 in any equation and find x

6x+5(-3/5)=1

6x=4

x=4/6=2/3

So Option B also correct.

5 0
3 years ago
how do i write and solve an equation for the total number of possible combinations from flipping a coin 10 times.
Tanzania [10]
Your answer is 1024.  2^ 10 
3 0
3 years ago
A sled is being held at rest on a slope that makes an angle theta with the horizontal. After the sled is released, it slides a d
Alenkasestr [34]

Answer:

μ =  Sin θ * d₁ / (d₂ - Cos θ*d₁)

d₂ = (d₁*Sin θ) / μ

Step-by-step explanation:

a) We apply The work-energy theorem

W = ΔE

W = - Ff*d

Ff = μ*N = μ*m*g

<em>Distance 1:</em>

- Ff*d₁ = Ef - Ei

⇒  - (μ*m*g*Cos θ)*d₁ = (Kf+Uf) - (Ki+Ui) = (Kf+0) - (0+Ui) = Kf - Ui

Kf = 0.5*m*vf² = 0.5*m*v²

Ui = m*g*h = m*g*d₁*Sin θ

then

- (μ*m*g*Cos θ)*d₁ = 0.5*m*v² - m*g*d₁*Sin θ  

⇒   - μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ   <em>(I)</em>

 

<em>Distance 2:</em>

<em />

- Ff*d₂ = Ef - Ei

⇒  - (μ*m*g)*d₂ = (0+0) - (Ki+0) = - Ki

Ki = 0.5*m*vi² = 0.5*m*v²

then

- (μ*m*g)*d₂ = - 0.5*m*v²

⇒   μ*g*d₂ = 0.5*v²     <em>(II)</em>

<em />

<em>If we apply (I) + (II)</em>

- μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ

μ*g*d₂ = 0.5*v²

 ⇒ μ*g (d₂ - Cos θ*d₁) = v² - g*d₁*Sin θ   <em>  (III)</em>

Applying the equation (for the distance 1) we get v:

vf² = vi² + 2*a*d = 0² + 2*(g*Sin θ)*d₁   ⇒   vf² = 2*g*Sin θ*d₁ = v²

then (from the equation <em>III</em>) we get

μ*g (d₂ - Cos θ*d₁) = 2*g*Sin θ*d₁ - g*d₁*Sin θ

⇒  μ (d₂ - Cos θ*d₁) = Sin θ * d₁

⇒   μ =  Sin θ * d₁ / (d₂ - Cos θ*d₁)

b)

If μ is a known value

d₂ = ?

We apply The work-energy theorem again

W = ΔK   ⇒   - Ff*d₂ = Kf - Ki

Ff = μ*m*g

Kf = 0

Ki = 0.5*m*v² = 0.5*m*2*g*Sin θ*d₁ = m*g*Sin θ*d₁

Finally

- μ*m*g*d₂ = 0 - m*g*Sin θ*d₁   ⇒   d₂ = Sin θ*d₁ / μ

3 0
3 years ago
Need some help with this question!
Veronika [31]
1. solve for x in first to just find nterms of y

x=12-y
sub that for x in other one
first divide that one by 2 to make it easier
2x-y=18
2(12-y)-y=18
24-2y-y=18
24-3y=18
minus 24 both sides
-3y=-6
divide -3
y=2

D is answer




2.
find intersection of x+y=5 and -2x+3y=6
or easiers, just test the intersections
wait, they all intersect in the same place
this is super easy
pick ANY point that is in that reigon and see if it is true

A, if we pick lets say (5,5)
that is false for x+y<5
not A

B
pick (10,0)
false for first one
not B

C
pick (0,0)
true for first
false for 2nd
not C


D. pick (-10,0)
true for first
true for 2nd


answer is D


answer is D for both questions
6 0
3 years ago
Almost sooo close guys just 5 more left sorry if it’s taking long
Andrei [34K]

Answer:

As a decimal its 6.34, If you round up then its 6.35

As a fraction its 400/63

As a mixed number its  6 22/63

5 0
3 years ago
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