The answer is D. 22.1.
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Answer:
5:2
10:4
15:6
20:8
Is this what format you wanted the answer?
Step-by-step explanation:
Answer:
The area of the resulting triangle will be: ![\boxed{A=900\:cm^2\:}](https://tex.z-dn.net/?f=%5Cboxed%7BA%3D900%5C%3Acm%5E2%5C%3A%7D)
Step-by-step explanation:
The area of a triangle is
![A=\frac{1}{2}\times base\times height](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20base%5Ctimes%20height)
Let us suppose
![A=\frac{1}{2}\times base\times height](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20base%5Ctimes%20height)
![A\:=\frac{1}{2}\times \:4\times \:18\:\:\:\:\:](https://tex.z-dn.net/?f=A%5C%3A%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%5C%3A4%5Ctimes%20%5C%3A18%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A)
![A=36\:cm^2\:](https://tex.z-dn.net/?f=A%3D36%5C%3Acm%5E2%5C%3A)
As the base and height are scaled a factor of 5.
so
base = 4 × 5 = 20
height = 18 × 5 = 90
as
![A=\frac{1}{2}\times base\times height](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20base%5Ctimes%20height)
![A\:=\frac{1}{2}\times \:20\times \:90](https://tex.z-dn.net/?f=A%5C%3A%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%5C%3A20%5Ctimes%20%5C%3A90)
![A=900\:cm^2\:](https://tex.z-dn.net/?f=A%3D900%5C%3Acm%5E2%5C%3A)
Therefore, the area of the resulting triangle will be: ![\boxed{A=900\:cm^2\:}](https://tex.z-dn.net/?f=%5Cboxed%7BA%3D900%5C%3Acm%5E2%5C%3A%7D)
Need more info, also correct grammar
Let n be the first even integer, and n+2 will be the second even integer. (Why? Think 2 and 4, 2+2=4. This is the case for every consecutive even integers).
n + 3(n+2) = 54
n + 3n + 6 = 54
4n = 48
n = 12, n+2 = 14