Ask question

Ask question

All categories

3 years ago

14

From an observation point A, a forest ranger sights a fire at a bearing of 215°50'. From a point b, 8 miles due west of A anothe

r ranger sights the fire at a bearing of 125°50'. Approximate to the nearest tenth of a mile, the distance of the fire from A.

2 answers:

kirill115 [55]3 years ago

7 0

Answer:

Step-by-steYou have two angles,

A=32°20'

B=57°40'

so, angle F at the fire, is 90°

d/5 = cosA = .845

d = 4.2 mi

If angle F had not been 90°, then using the law of sines,

d/sinA = 5/sinF

for this problem, sinF = 1p explanation:

Alisiya [41]3 years ago

5 0

Answer:

Step-by-step explanation:

You might be interested in

Hello! I really don't understand this question. Please answer it, it is due tomorrow! Also, please answer it in the most simple

borishaifa [10]

Answer:

Just because Michelle checked out 20% of her borrowed books were fictions does not mean Michael had more books. For example, Michelle could have borrowed 100 books, which would result into her borrowing 20 fiction books while Michael could have borrowed just 1 fiction book with a 100% of his borrowed books being a fiction book.

Step-by-step explanation:

Just because Michelle checked out 20% of her borrowed books were fictions does not mean Michael had more books. For example, Michelle could have borrowed 100 books, which would result into her borrowing 20 fiction books while Michael could have borrowed just 1 fiction book with a 100% of his borrowed books being a fiction book.

In other words, percentage is just the simplied ratio of something. Percentage cannot account for the original value and its original value cannot be assumed that it is small just because the percentage is small.

6 0

3 years ago

It was in -5 degrees Celsius Copenhagen and -10 degrees Celsius in Oslo. Which city was<br> colder?

Anvisha [2.4K]

Answer:

Oslo

Step-by-step explanation:

The farther the number from zero at the right hand side, the colder.

So its Oslo

I hope this helps!

8 0

2 years ago

Solve the system of equation by guess sidle method

lilavasa [31]

Answer: The solution is,

$x_1\approx 0.876$

$x_2\approx 0.419$

$x_3\approx 0.574$

Step-by-step explanation:

Given equations are,

$8x_1 + x_2 + x_3 = 8$

$2x_1 + 4x_2 + x_3 = 4$

$x_1 + 3x_2 + 5x_3 = 5$ ,

From the above equations,

$x_1=\frac{1}{8}(8-x_2-x_3)$

$x_2=\frac{1}{4}(4-2x_1-x_3)$

$x_3=\frac{1}{5}(5-x_1-3x_2)$

First approximation,

$x_1(1)=\frac{1}{8}(8-(0)-(0))=1$

$x_2(1)=\frac{1}{4}(4-2(1)-(0))=0.5$

$x_3(1)=\frac{1}{5}(5-1-3(0.5))=0.5$

Second approximation,

$x_1(2)=\frac{1}{8}(8-(0.5)-(0.5))=0.875$

$x_2(2)=\frac{1}{4}(4-2(0.875)-(0.5))=0.4375$

$x_3(2)=\frac{1}{5}((0.875)-3(0.4375))=0.5625$

Third approximation,

$x_1(3)=\frac{1}{8}(8-(0.4375)-(0.5625))=0.875$

$x_2(3)=\frac{1}{4}(4-2(0.875)-(0.5625))=0.421875$

$x_3(3)=\frac{1}{5}(5-(0.875)-3(0.421875))=0.571875$

Fourth approximation,

$x_1(4)=\frac{1}{8}(8-(0.421875)-(0.571875))=0.875781$

$x_2(4)=\frac{1}{4}(4-2(0.875781)-(0.571875))=0.419141$

$x_3(4)=\frac{1}{5}(5-(0.875781)-3(0.419141))=0.573359$

Fifth approximation,

$x_1(5)=\frac{1}{8}(8-(0.419141)-(0.573359))=0.875938$

$x_2(5)=\frac{1}{4}(4-2(0.875938)-(0.573359))=0.418691$

$x_3(5)=\frac{1}{5}(5-(0.875938)-3(0.418691))=0.573598$

Hence, by the Gauss Seidel method the solution of the given system is,

$x_1\approx 0.876$

$x_2\approx 0.419$

$x_3\approx 0.574$

4 0

3 years ago

⦁ Aisha combined 3/8 cup of flour and 3/5 cup of flour. She concluded that she had 18/40 cup of flour. Is her answer reasonable?

mr Goodwill [35]

Answer:

Step-by-step explanation:

3/8 + 3/5 = 15/40 + 24/40 = 39/40

no...her answer is not reasonable.....she would have more then twice as much as her conclusion of 18/40

7 0

3 years ago

Read 2 more answers

A swimming pool can be filled in 16 hours if water enters through a pipe alone, or in 23 hours if water enters through a hose al

Temka [501]

Answer:

Step-by-step explanation: 23x23+16x16=785

(785

28.0

4 0

4 years ago