Keywords
quadratic equation, discriminant, complex roots, real roots
we know that
The formula to calculate the <u>roots</u> of the <u>quadratic equation</u> of the form 
is equal to
where
The <u>discriminant</u> of the <u>quadratic equation</u> is equal to
if 
----> the <u>quadratic equation</u> has two <u>real roots</u>
if 
----> the <u>quadratic equation</u> has one <u>real root</u>
if 
----> the <u>quadratic equation</u> has two <u>complex roots</u>
in this problem we have that
the <u>discriminant</u> is equal to 
so
the <u>quadratic equation</u> has two <u>complex roots</u>
therefore
the answer is the option A
There are two complex roots
Answer:
1,3, and 7th option.
Step-by-step explanation:
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We're looking for a scalar function 
such that 
. That is,
Integrate the first equation with respect to 
:
Differentiate with respect to 
:
Integrate with respect to :
So 
is indeed conservative with the scalar potential function
where 
is an arbitrary constant.
Answer:
25
Step-by-step explanation:
306/6 is 51 is you add one to one side and take away the other the six numbers become: 46, 48, 50, 52, 54, 56 as you added one to one side substituting the other you took away from, therefore the smallest would be 46.
