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2 years ago

11

NEED HELP!!! WITH PROBLEM

1 answer:

pantera1 [17]2 years ago

7 0

Answer:

x=32 hope it helps, if it does can i get 5.0 or brainliest

Step-by-step explanation:

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2 years ago

There are 6 teams in a baseball league. A schedule is made such that each team plays every other team 5 times. How many games mu

sveta [45]

6 teams 5 times the key word is times this means multiply so 6x5=30

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2 years ago

Tell how you can use tools to solve a math <br> problem

castortr0y [4]

By measuring and knowing the wait of the ounces and height

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3 years ago

Complete each trinomial such that it can be rewritten in the form a(x+b)^2 or a(x-b)^2

scoundrel [369]

The value of the expression in the form a(x+b)^2 is 1.5(x+2)^2 - 4

<h3>Vertex Form of a quadratic expression</h3>

Given the quadratic expressions

1.5x^2+6x+......

1.5(x^2 + 4x)

Using the completing the square method

The coefficient of x = 4

Half of the coefficient = 4/2 = 2

The square of the result = 2^2 = 4

The equation is expressed as:

f(x) = 1.5(x^2+4x+ 4) - 4

f(x) = 1.5(x+2)^2 - 4

Hence the value of the expression in the form a(x+b)^2 is 1.5(x+2)^2 - 4

Learn more on completing the square method here: brainly.com/question/1596209

6 0

2 years ago

Can you answer these please many thanks

givi [52]

Given: (a) $2(x+3)=2x+6$ and (b) $4(y-3)=4y-12$ .

To find: The expanded form of the given expressions.

(c) $4(m+n)=4m+4n$ (using $a(b+c)=ab+ac$ )

(d) $3(5-q)=15-3q$ (using $a(b-c)=ab-ac$ )

(e) $5(2c+1)=10c+5$ (using $a(b+c)=ab+ac$ )

(f) $3(2x-5)=6x-15$ (using $a(b-c)=ab-ac$ )

(g) $7(4b-1)=28b-7$ (using $a(b-c)=ab-ac$ )

(h) $3(2x+y-5)=3((2x+y)-5)$

⇒ $3(2x+y-5)=3(2x+y)-15$ (using $a(b-c)=ab-ac$ )

⇒ $3(2x+y-5)=6x+3y-15$ (using $a(b+c)=ab+ac$ )

(i) $2(6a-4b+3)=2((6a-4b)+3)$

⇒ $2(6a-4b+3)=2(6a-4b)+6$ (using $a(b+c)=ab+ac$ )

⇒ $2(6a-4b+3)=12a-8b+6$ (using $a(b-c)=ab-ac$ )

(j) $6(m+n+p)=6((m+n)+p)$

⇒ $6(m+n+p)=6(m+n)+6p$ (using $a(b+c)=ab+ac$ )

⇒ $6(m+n+p)=6m+6n+6p$ (using $a(b+c)=ab+ac$ )

(k) $y(y+2)=y^2+2y$ (using $a(b+c)=ab+ac$ )

(l) $g(g-3)=g^2-3g$ (using $a(b-c)=ab-ac$ )

(m) $n(4-n)=4n-n^2$ (using $a(b-c)=ab-ac$ )

(n) $a(b+c)=ab+ac$ (using $a(b+c)=ab+ac$ )

(o) $s(3s-4)=3s^2-4s$ (using $a(b-c)=ab-ac$ )

(p) $2x(x+5)=2x^2+10x$ (using $a(b+c)=ab+ac$ )

(q) $4y(x-3)=4xy-12y$ (using $a(b-c)=ab-ac$ )

(r) $5a(2b-5)=10ab-25a$ (using $a(b-c)=ab-ac$ )

(s) $4a(3b+2c)=12ab+8ac$ (using $a(b+c)=ab+ac$ )

(t) $5p(4p-5q)=20p^2-25pq$ (using $a(b-c)=ab-ac$ )

6 0

3 years ago