Answer:
AE = 15 cm; ED = 18 cm; AD = 15 cm (given)
Step-by-step explanation:
ΔBEC ~ ΔAED so ...
AD/BC = AE/BE = (BE+AB)/BE = 1 + AB/BE
Substituting given numbers (lengths in centimeters), we have ...
15/10 = 1 + 5/BE
1/2 = 5/BE
BE = 10
Similarly, ...
1/2 = 6/CE
CE = 12
Then the unknown sides are ...
AE = AB + BE = 5 + 10 = 15 . . . cm
ED = CE + CD = 12 + 6 = 18 . . . cm
The best answer is 1.435 ·103 because while they both are really small for a rail road track that one is bigger. the final answer for that is 147.805mm.
The answer is a since 150/6 is 25
<span>The cube’s sides measures 6 inches and the measurement for
the rectangular box is that it is 10 inches long, 4 inches thick and 4 inches
high. To compute for the volume of a cube you must use the formula of V = a3
and for the rectangular prism is V = l x w x h.</span>
<span>Cube: V = 6^3
</span> <span>V = 216 inches^3</span>
<span>Rectangular Prism: V
= 10 x 4 x 4</span>
<span>
V
= 160 inches^3</span>
To identify how much greater the volume the cube from the
rectangular box we subtract their volumes.
N = C – R where N stands for the unknown C for the volume of
cube and R for the volume of Rectangular Box
<span>
N = 216 inches^3 – 160 inches^3
</span>
<span>N = 56 inches^3</span>
<span>
So the cube is 56 inches3 greater than the
rectangular box.</span>
Answer:
3x²-29x+4
Step-by-step explanation:
3x²-x-4=-30x
0=-30x-3x²+x+4
0=-3x²-29x+4
