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Marina86 [1]
3 years ago
12

Experiments with repeated independent trials will be described by the binomial distribution if

Mathematics
1 answer:
bija089 [108]3 years ago
7 0

Answer:

d. each trial has exactly two outcomes whose probabilities do not change

Step-by-step explanation:

A binomial experiment is one where there are exactly two outcomes for each trial and probability for getting success is constant in each trial.

In other words, each trial is independent of the other.

The trials need not be continuous nor time between trials to be constant.

Since trials are to be independent, each trial cannot influence the next.

Only option d is right.

d. each trial has exactly two outcomes whose probabilities do not change

Examples are tossing of coins, throwing dice, drawing cards or balls with replacement, etc

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Firdavs [7]

Answer:

4u³

Step-by-step explanation:

2/3u × 4/2u² = 4/3u³

4/3u³ × 3/1 = 4u³

6 0
2 years ago
Read 2 more answers
A football team has a probability of .75 of winning when playing any of the other four teams in its conference. If the games are
Alexeev081 [22]

Answer:

0.3164 = 31.64% probability the team wins all its conference games

Step-by-step explanation:

For each conference game, there are only two possible outcomes. Either the team wins it, or they lose. The probability of winning a game is independent of any other game. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A football team has a probability of .75 of winning when playing any of the other four teams in its conference.

The probability means that p = 0.75, and four games means that n = 4

If the games are independent, what is the probability the team wins all its conference games?

This is P(X = 4). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{4,4}.(0.75)^{4}.(0.25)^{0} = 0.3164

0.3164 = 31.64% probability the team wins all its conference games

4 0
3 years ago
The formula for the resistance of a conductor with voltage V and current I is r= v/1. Solve for V.
VikaD [51]
V=i x r is the formula 
8 0
2 years ago
Olivia bowled 5 games. Her scores were 80, 95, 100, 85, and 95. What is the mean of her scores for the 5 games? * A. 20 B. 72 C.
egoroff_w [7]
The answer is gonna be C,which is 91.Hope this helps
5 0
3 years ago
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HELP ME PLS I NEED THIS NOW
Lyrx [107]

r = radius

Arc length = 2(3.14)r

7.9 cm = r

Plug our values in

Arc length = 2(3.14)(7.9 cm)

Arc length = 49.6 cm

4 0
3 years ago
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