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3 years ago

Experiments with repeated independent trials will be described by the binomial distribution if

Mathematics

1 answer:

bija089 [108]3 years ago

7 0

Answer:

d. each trial has exactly two outcomes whose probabilities do not change

Step-by-step explanation:

A binomial experiment is one where there are exactly two outcomes for each trial and probability for getting success is constant in each trial.

In other words, each trial is independent of the other.

The trials need not be continuous nor time between trials to be constant.

Since trials are to be independent, each trial cannot influence the next.

Only option d is right.

d. each trial has exactly two outcomes whose probabilities do not change

Examples are tossing of coins, throwing dice, drawing cards or balls with replacement, etc

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Solve for x. Express the answer in simplest form. <br>2/1 = 8x - 2/ 9

oksano4ka [1.4K]

2=8x-2/9
add 2/9 to both sides
2 and 2/9=8x
2=18/9
2 and 2/9=18/9+2/9=20/9
20/9=8x
multiply both sides by 9
20=72x
divide boht isdes by 72
20/72=x=5/18

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3 years ago

Every evening Jenna empties her pockets

rodikova [14]

Answer:

Step-by-step explanation:

1 dime = 10

1 quarter=25

x=number of coins - dimes

y= number of coins - quarters

x (10)+y(25)=10.25

x+y=50

x= 50-y

x(10)+y(25)=1025

(50-y)(10)+25y =1025

500-10y+25y=1025

500+15y=1025

15y= 1025 - 500

15y=525

y=525/15

y=35

x= 50-35=15

3 0

2 years ago

Ms. Cannon is a tutor. She charges $ 25 for travel time and $ 35 for each hour, h, she tutors. What expression represents the to

wolverine [178]

Answer:

25 + 35h

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

WHAT IS THE REMAINDER WHEN <img src="https://tex.z-dn.net/?f=32%5E%7B37%5E%7B32%7D%20%7D" id="TexFormula1" title="32^{37^{32} }"

Feliz [49]

Recall Euler's theorem: if $\gcd(a,n) = 1$ , then

$a^{\phi(n)} \equiv 1 \pmod n$

where $\phi$ is Euler's totient function.

We have $\gcd(9,32) = 1$ - in fact, $\gcd(9,32^k)=1$ for any $k\in\Bbb N$ since $9=3^2$ and $32=2^5$ share no common divisors - as well as $\phi(9) = 6$ .

Now,

$37^{32} = (1 + 36)^{32} \\\\ ~~~~~~~~ = 1 + 36c_1 + 36^2c_2 + 36^3c_3+\cdots+36^{32}c_{32} \\\\ ~~~~~~~~ = 1 + 6 \left(6c_1 + 6^3c_2 + 6^5c_3 + \cdots + 6^{63}c_{32}\right) \\\\ \implies 32^{37^{32}} = 32^{1 + 6(\cdots)} = 32\cdot\left(32^{(\cdots)}\right)^6$