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shusha [124]
3 years ago
8

Solve for y in the following equation.

Mathematics
1 answer:
Tju [1.3M]3 years ago
5 0

Answer:

y = \frac{z^2 - x}{2}

Step-by-step explanation:

Given:

\sqrt{x + 2y} = z

Required:

Solve for y (make y the subject of the formula)

SOLUTION:

\sqrt{x + 2y} = z

Square both sides

(\sqrt{x + 2y})^2 = z^2

x + 2y = z^2

Subtract both sides by x

2y = z^2 - x

Divide both sides by 2

y = \frac{z^2 - x}{2}

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2nd table:
.. 128 -135 = -7; 105 -128 = -23; 72 -105 = -33 . . . . first differences
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4th table:
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