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3 years ago

11

PLEASE HELP ME WITH THIS PLEASE EXPLAIN

1 answer:

siniylev [52]3 years ago

6 0

When the x values are evenly spaced, as they are here, the second differences are constant when the function is quadratic.

1st table:
.. 2 -4 = -2; 1 -2 = -1; 0.5 -1 = -0.5 . . . . first differences
.. -1 -(-2) = 1; -0.5 -(-1) = 0.5 . . . . . . . . . second differences are different

2nd table:
.. 128 -135 = -7; 105 -128 = -23; 72 -105 = -33 . . . . first differences
.. -23 -(-7) = -16; -33 -(-23) = -10 . . . . . . . . . . . . . . . second differences are different

3rd table:
.. -23.2 -(-23.4) = 0.2; -23 -(-23.2) = 0.2 . . . . . first differences are constant. This is a linear function.

4th table:
.. 56 -90 = -34; 26 -56 = -30; 0 -26 = -26; -22 -0 = -22; -40 -(-22) = -18
.. -30 -(-34) = 4; -26 -(-30) = 4; -22 -(-26) = 4; -18 -(-22) = 4 . . . . second differences are constant at 4.

The 4th selection is appropriate.

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Solve the following problem. Round the one decimal place if necssary.

dmitriy555 [2]

Cosθ = adjacent / hypotenuse

$\cos(47) = \frac{28}{x} \\ 0.68 = \frac{28}{x} \\ x = \frac{28}{0.68} \\ x = 41.1 \\ x = 41$

I hope I helped you^_^

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3 years ago

Find the equation of line that goes through coordinates (-4,-2) and (-3,-5) ?

frutty [35]

Answer: y = -3x/7 + 26/7

Step-by-step explanation: Using the "slope-intercept" format, we can set up 2 equations, using the given points.

The format: y = mx + b, where m is the slope and b is the y-intercept (where x = 0)

To find m and b, we need 2 equations which we get using the 2 given points:

(-3,5):

5 = m(-3) + b (equation 1)

(4,2):

2 = m(4) + b (equation 2)

Subtract #2 from #1 to get:

3 = -7m

m = -3/7

Then, using equation 1, find b:

5 = (-3/7)*(-3) + b

b = 5 - 9/7 = 26/7

The equation is then:

y = -3x/7 + 26/7

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2 years ago

What is the answer and how do I solve the problem 2739 divided by 3

nexus9112 [7]

Answer:

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4 0

3 years ago

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Help me please i need a good grade

s2008m [1.1K]

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4 0

3 years ago

Angle θ is in standard position. If (8, -15) is on the terminal ray of angle θ, find the values of the trigonometric functions.

notsponge [240]

ANSWER

$\sin( \theta) = - \frac{15}{17}$

$\csc( \theta) = - \frac{17}{15}$

$\cos( \theta) = \frac{8}{17}$

$\sec( \theta) = \frac{17}{8}$

$\tan( \theta) = - \frac{15}{8}$

$\cot( \theta) = - \frac{8}{15}$

EXPLANATION

From the Pythagoras Theorem, the hypotenuse can be found.

${h}^{2} = 1 {5}^{2} + {8}^{2}$

${h}^{2} = 289$

$h = \sqrt{289}$

$h = 17$

The sine ratio is negative in the fourth quadrant.

$\sin( \theta) = - \frac{opposite}{hypotenuse}$

$\sin( \theta) = - \frac{15}{17}$

The cosecant ratio is the reciprocal of the sine ratio.

$\csc( \theta) = - \frac{17}{15}$

The cosine ratio is positive in the fourth quadrant.

$\cos( \theta) = \frac{adjacent}{hypotenuse}$

$\cos( \theta) = \frac{8}{17}$

The secant ratio is the reciprocal of the cosine ratio.

$\sec( \theta) = \frac{17}{8}$

The tangent ratio is negative in the fourth quadrant.

$\tan( \theta) = - \frac{opposite}{adjacent}$

$\tan( \theta) = - \frac{15}{8}$

The reciprocal of the tangent ratio is the cotangent ratio

$\cot( \theta) = - \frac{8}{15}$

8 0

3 years ago

Read 2 more answers