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3 years ago

Find the values of A, B, C, and D in this equation:

Mathematics

1 answer:

uranmaximum [27]3 years ago

3 0

A= 54
B= 7
C= 21
D= 86
Your welcome I hope this helps

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The mean and standard deviation of a normal distribution are 150 and 12 respectively. What percentage of values lie between:

Semenov [28]

Answer:

Step-by-step explanation:

Use a calculator with built-in statistical functions. The function applying here is normcdf(, the "cumulative density function."

(a) The percentage of values lying between 138 and 162 is

norm(138,162, 150, 12), which comes out to 0.683, or 68.3%.

(b) Find norm(126, 174, 150,12): 0.945, or 94.5%

(d) Find norm(162, 174,150,12): 0.136, or 13.6%

8 0

4 years ago

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the population of a city has decreased by 36% since it was last measured. if the current population is 17600 what was the previo

Savatey [412]

Answer:

23,936

Step-by-step explanation:

so get your 17600 times it by 0.36 which gets you 6,336 then add that to 17,600 =23,936

That's how you get your answer

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3 years ago

Solve for x <br>please I need the answer the picture shows the question

ozzi

Answer:

15inch

Step-by-step explanation:

X^2=8^2+7^2

7 0

2 years ago

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Wright an inequality for the graph

Lerok [7]

Answer:

Y >= ABS(x-5) + 1

Step-by-step explanation:

Any graph that forms a "V" involves absolute value. So what equation would give the vertex y=1 at x=5, ABS(X-5) + 1.

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3 years ago

The diameter of a iron sphere is 8 cm. It is beaten and drawn into a wire with a diameter of 2 mm. Find the length of the wire.

djyliett [7]

Answer : The length of the wire is, 8533 cm

Step-by-step explanation :

As the iron sphere is beaten and drawn into a wire. That means, their volume will be equal.

Volume of iron sphere = Volume of cylindrical wire

The formula will be:

$\frac{4}{3}\pi r_1^3=\pi r_2^2h$

where,

$r_1$ = radius of sphere = $\frac{Diamtere}{2}=\frac{8cm}{2}=4cm$

$r_2$ = radius of cylindrical wire = $\frac{Diamtere}{2}=\frac{2mm}{2}=1mm=0.1cm$

h = height of cylindrical wire or length of wire

Now put all the given values in the above formula, we get:

$\frac{4}{3}\pi r_1^3=\pi r_2^2h$

$\frac{4}{3}\times r_1^3=r_2^2h$

$\frac{4}{3}\times (4)^3=(0.1)^2h$

$h=8533.33cm\approx 8533cm$

Therefore, the length of the wire is, 8533 cm

6 0

3 years ago