Answer:
![\log_{2} [\frac{x^{3}(x + 4)}{3}]](https://tex.z-dn.net/?f=%5Clog_%7B2%7D%20%5B%5Cfrac%7Bx%5E%7B3%7D%28x%20%2B%204%29%7D%7B3%7D%5D)
Step-by-step explanation:
We have to write the following logarithmic expression as a single logarithm.
The given expression is
![3\log_{2} x - [\log_{2} 3 - \log_{2}(x + 4)]](https://tex.z-dn.net/?f=3%5Clog_%7B2%7D%20x%20-%20%5B%5Clog_%7B2%7D%203%20-%20%5Clog_%7B2%7D%28x%20%2B%204%29%5D)
= 
{Since,
, from the properties of logarithmic function }
= 
{Since,
, which also a logarithmic property}
= ![\log_{2} [\frac{x^{3}}{\frac{3}{x + 4}}]](https://tex.z-dn.net/?f=%5Clog_%7B2%7D%20%5B%5Cfrac%7Bx%5E%7B3%7D%7D%7B%5Cfrac%7B3%7D%7Bx%20%2B%204%7D%7D%5D)
=
(Answer)
let's firstly convert the mixed fractions to improper fractions and then subtract, bearing in mind that the LCD of 4 and 2 is 4.
![\bf \stackrel{mixed}{8\frac{3}{4}}\implies \cfrac{8\cdot 4+3}{8}\implies \stackrel{improper}{\cfrac{35}{4}}~\hfill \stackrel{mixed}{7\frac{1}{2}}\implies \cfrac{7\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{15}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{35}{4}-\cfrac{15}{2}\implies \stackrel{\textit{using the LCD of 4}}{\cfrac{(1)35~~-~~(2)15}{4}}\implies \cfrac{35-30}{4}\implies \cfrac{5}{4}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B8%5Cfrac%7B3%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B8%5Ccdot%204%2B3%7D%7B8%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B35%7D%7B4%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B7%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B7%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B15%7D%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B35%7D%7B4%7D-%5Ccfrac%7B15%7D%7B2%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Busing%20the%20LCD%20of%204%7D%7D%7B%5Ccfrac%7B%281%2935~~-~~%282%2915%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B35-30%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B4%7D)