Let x and y be the 2 parts of 15 ==> x + y=15 (given)
Reciprocal of x and y ==> 1/x +1/y ==> 1/x + 1/y = 3/10 (given)
Let's solve 1/x + 1/y = 3/10 . Common denominator = 10.x.y (reduce to same denominator)
==> (10y+10x)/10xy = 3xy/10xy ==> 10x+10y =3xy
But x+y = 15 , then 10x+10y =150 ==> 150=3xy and xy = 50
Now we have the sum S of the 2 parts that is S = 15 and
their Product = xy =50
Let's use the quadratic equation for S and P==> X² -SX +P =0
Or X² - 15X + 50=0, Solve for X & you will find:
The 1st part of 15 is 10 & the 2nd part is 5
Answer:
No solutions
Step-by-step explanation:
3x+4y=-4
15x+20y=-22
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-5(3x+4y)=-5(-4) multiply 1st equation by -5 so you can eliminate the variables
-15x-20y=20. Modified 1st equation
15x+20y=-22. 2nd equation
0+0=-2. Added two equations together
since 0 does not equal -2, there is no solution.
Answer: x + y = z
Example:
Lets say if x 5 and y is 10 then z would equal 15.
5 + 10 = 15
Hope this helped! :)
Answer:
(-5, 6) is not a solution.
Step-by-step explanation:
6=2(-5)+4
6=-10+4
-10+4=-6, not 6.
Answer: here u go ig
Step-by-step explanation:
