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ycow [4]
2 years ago
5

Pls help will give brainiest

Mathematics
1 answer:
Anastaziya [24]2 years ago
7 0

Answer:

2

Step-by-step explanation:

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Decide which measurement is greater. Place the correct symbol ( <, >, =) on the line between the measurements.
laila [671]

Answer:

5>18 and 25

1 and 4>32

3<8

13<4

4<9

i hope this helped :)

Step-by-step explanation:

5 0
2 years ago
K-x=y+w, for x<br> Solve the equation for each indicated variable
sveta [45]

Answer:

-x=y+w-k

-x.-1=-1.(y+w-k)

x=-y-w+k

8 0
3 years ago
The expression 7kl – 3k(4k + 2l) is equivalent to:​
koban [17]

Answer:

- 12k² + kl

Step-by-step explanation:

Given

7kl - 3k(4k + 2l) ← distribute parenthesis by - 3

= 7kl - 12k² - 6kl ← collect like terms

= - 12k² + kl

6 0
3 years ago
an plumber charges a flat rate of $25 for a job and $15 for each hour that he works on the job.how many hours did the plumber wo
Illusion [34]

Answer: 3 hours

Step-by-step explanation:

If you add up 25+15=40 if you add up 40+15=55, 55+15=70, 70+15=85

4 0
3 years ago
Use an appropriate Taylor series to find the first four nonzero terms of an infinite series that is equal to sin(5/2).
koban [17]

Answer:

2.5, -2.61, 0.81, -0.12

Step-by-step explanation:

The taylor series of the function sin(x) around zero is given by

sin(x)=\sum_{n=0}^{\infty}\dfrac{(-1)^k}{(2k-1)!}x^{2k+1}=x-\dfrac{x^3}{3!}+\dfrac{x^5}{5!}-\dfrac{x^7}{7!}

Therefore,

\sin(\frac{5}{2})=\dfrac{5}{2}-\dfrac{[\frac{5}{2}]^3}{3!}+\dfrac{[\frac{5}{2}]^5}{5!}-\dfrac{[\frac{5}{2}]^7}{7!}+...

hence the first four nonzero terms of the series are

\dfrac{5}{2}=2.5\\\\-\dfrac{[\frac{5}{2}]^3}{3!} \approx -2.61\\\\\dfrac{[\frac{5}{2}]^5}{5!} \approx 0.81\\\\-\dfrac{[\frac{5}{2}]^7}{7!} \approx -0.12

6 0
3 years ago
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