All categories

3 years ago

Please help fast i am struggling

Mathematics

1 answer:

klemol [59]3 years ago

6 0

B is the correct answer for your question I do believe, I hope that helped you. If not I am sorry, I tried to answer fast for you.

You might be interested in

What is the y value of the solution to the system of equations shown below y = 22 - 6 y = 50 – 21

zhannawk [14.2K]

Answer:

22-6y= 29

-6y=29-22

-6y=7

y=-7/6

3 0

3 years ago

Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and

zzz [600]

Answer:

$\bold{sin(38^\circ)=cos(52^\circ)}$

Step-by-step explanation:

Given that $\triangle KJL$ is a right angled triangle.

$\angle JKL = 52^\circ\\\angle KLJ = 38^\circ$

and

$\angle KJL = 90^\circ$

Kindly refer to the attached image of $\triangle KJL$ in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given $\triangle KJL$ .

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

$sin\theta =\dfrac{Perpendicular}{Hypotenuse}$

$sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}$ ....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

$cos\theta =\dfrac{Base}{Hypotenuse}$

$cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}$ ....... (2)

By (1) and (2):

sin(38°) $\neq$ cos(38°).

$cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL}$ ...... (3)

Comparing equations (1) and (3):

we get the both are same.

$\therefore \bold{sin(38^\circ)=cos(52^\circ)}$

6 0

3 years ago

Which strategy would not correctly solve this story problem? Ms. Bailey's cat had 10 kittens. There were 5 white kittens, 3 blac

stellarik [79]

D would not correctly solve the problem it is adding more kittens instead of eliminating the ones already known

5 0

3 years ago

What is the permeter of square ABCD?

marshall27 [118]

Answer:

24.3 units (3 s.f.)

Step-by-step explanation:

Since a square has 4 equal sides,

perimeter of ABCD= 4(length of AB)

Distance between 2 points

= $\sqrt{(y1 - y2)^{2} + (x1 - x2)^{2} }$

Length of AB

$= \sqrt{( { - 2 - 4)}^{2} + {(2 - 3)}^{2} } \\ = \sqrt{( - 6)^{2} + ( - 1)^{2} } \\ = \sqrt{37}$

perimeter of ABCD

$= 4 \sqrt{37} \\ = 24.3 \: units \: (3 \: s.f.)$

7 0

3 years ago

PLEASE PLEASE HELP IM TIMED!! Just look at the picture

barxatty [35]

The first one A 7/2
You can just round up 6.75 -> 7 and 1.67->2

4 0

2 years ago

Read 2 more answers