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statuscvo [17]
3 years ago
9

Please help fast i am struggling

Mathematics
1 answer:
klemol [59]3 years ago
6 0
B is the correct answer for your question I do believe, I hope that helped you. If not I am sorry, I tried to answer fast for you.
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What is the y value of the solution to the system of equations shown below y = 22 - 6 y = 50 – 21​
zhannawk [14.2K]

Answer:

22-6y= 29

-6y=29-22

-6y=7

y=-7/6

3 0
3 years ago
Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and
zzz [600]

Answer:

\bold{sin(38^\circ)=cos(52^\circ)}

Step-by-step explanation:

Given that \triangle KJL is a right angled triangle.

\angle JKL = 52^\circ\\\angle KLJ = 38^\circ

and

\angle KJL = 90^\circ

Kindly refer to the attached image of \triangle KJL in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given \triangle KJL.

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

sin\theta =\dfrac{Perpendicular}{Hypotenuse}

sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

cos\theta =\dfrac{Base}{Hypotenuse}

cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}....... (2)

By (1) and (2):

sin(38°) \neq cos(38°).

cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL} ...... (3)

Comparing equations (1) and (3):

we get the both are same.

\therefore \bold{sin(38^\circ)=cos(52^\circ)}

6 0
3 years ago
Which strategy would not correctly solve this story problem? Ms. Bailey's cat had 10 kittens. There were 5 white kittens, 3 blac
stellarik [79]
D would not correctly solve the problem it is adding more kittens instead of eliminating the ones already known
5 0
3 years ago
What is the permeter of square ABCD?
marshall27 [118]

Answer:

24.3 units (3 s.f.)

Step-by-step explanation:

Since a square has 4 equal sides,

perimeter of ABCD= 4(length of AB)

Distance between 2 points

=\sqrt{(y1 - y2)^{2} + (x1 - x2)^{2}  }

Length of AB

=  \sqrt{( { - 2 - 4)}^{2}  +  {(2 - 3)}^{2} }  \\  =  \sqrt{( - 6)^{2}  + (  - 1)^{2} }  \\  =  \sqrt{37}

perimeter of ABCD

= 4 \sqrt{37}  \\  = 24.3 \: units \: (3 \: s.f.)

7 0
3 years ago
PLEASE PLEASE HELP IM TIMED!! Just look at the picture
barxatty [35]
The first one A 7/2
You can just round up 6.75 -> 7 and 1.67->2
4 0
2 years ago
Read 2 more answers
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