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svlad2 [7]
3 years ago
8

The answer to a division problem is greater than the divisor always never or sometimes pick one

Mathematics
2 answers:
Ksenya-84 [330]3 years ago
8 0
Sometimes..... 
hope this helps! :)
mylen [45]3 years ago
7 0
Sometimes.

2/.5 = 4, so it can't be never, and 2/2 = 1, so it can't be always.
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Choose the equation below that represents the line passing through the point (−2, −3) with a slope of −6.
lubasha [3.4K]
Y = mx + b
slope(m) = -6
(-2,-3)...x = -2 and y = -3
now we sub....we r looking for b, the y int
-3 = -6(-2) + b
-3 = 12 + b
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-15 = b

so ur equation is : y = -6x - 15

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3 years ago
In the expression 2a-5+4a-9, name the constants​
Vika [28.1K]

Answer:

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3 years ago
Katherine buys a tv with a normal price of $200 and she has a 25% off coupon. How much money did she save????
andrey2020 [161]

Given:

Normal price of a tv = $200

Coupon = 25% off

To find:

The money saved by Katherine.

Solution:

Katherine buys a tv with a normal price of $200 and she has a 25% off coupon. It means, the money saved by Katherine is 25% of normal price of tv, i.e., $200.

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6 0
3 years ago
You can use an arithmetic operator to return the modulus of a calculation, which is the ____ when you divide one number by anoth
balandron [24]

Answer:

<u>Residue</u>

Step-by-step explanation:

Let a and b be integers. We define a mod b to be the residue of dividing a by b. For example, if a evenly divides b, then a mod b=0, 20 mod 6= 2. The modulus operator is widely used in programming, and it is convenient when a and b are large numbers.

a mod b is always a nonnegative integer. In fact, 0≤ a mod b≤ |b-1| by the division algorithm. a and b can also be negative integers. Since 8=-(-5)+3 then 8 mod -5= 3.

As a final example, some known properties can be rewritten in terms of mod. a mod 2=0 if and only if a is even. a mod 2=1 if and only if a is odd.

7 0
3 years ago
Pls answer question :)
inysia [295]

okay im not sure but maybe try to find a number that can be = to 18 and that might be y

6 0
3 years ago
Read 2 more answers
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