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Stolb23 [73]
2 years ago
11

Xx squared - XY + x squared - xy ​

Mathematics
2 answers:
creativ13 [48]2 years ago
6 0

In case your expression is:

x^2\:-\:xy\:+\:x^2\:-\:xy

Solution:

Given the expression

x^2\:-\:xy\:+\:x^2\:-\:xy

Group like terms

x^2\:-\:xy\:+\:x^2\:-\:xy=x^2+x^2-xy-xy

Add similar elements: x²+x² = 2x²

                                  =2x^2-xy-xy

Add similar elements: -xy-xy = -2xy

                                    =2x^2-2xy

Thus,

x^2-xy+x^2-xy=2x^2-2xy

In case your expression is:

\left(xx\right)^2\:-\:xy\:+\:x^2\:-\:xy

Solution:

Given the expression

\left(xx\right)^2\:-\:xy\:+\:x^2\:-\:xy

Group like terms

\left(xx\right)^2\:-\:xy\:+\:x^2\:-\:xy=x^2-xy-xy+\left(xx\right)^2

Add similar elements: -xy-xy = -2xy

                                       =x^2-2xy+\left(xx\right)^2

as (xx)² = x⁴

so                                      =x^2-2xy+x^4

Therefore, we conclude that:

  • \left(xx\right)^2\:-\:xy\:+\:x^2\:-\:xy=x^2-2xy+x^4                                  
EastWind [94]2 years ago
4 0

Answer and Step-by-step explanation:

x^{2} - xy + x^{2} -xy\\\\2x^{2} -2xy

This is the answer.

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3 years ago
Across which axis was point A reflected​
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Step-by-step explanation:

When we reflect a point A across the x-axis, the value of 'y' gets negated, but the value of 'x' remains unchanged.

In other words, when point P with coordinates (x, y) is reflected across the x-axis and mapped onto point P', the coordinates of P' will be (x, -y).

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P(x, y) → P'(x, -y)

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