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2 years ago

Xx squared - XY + x squared - xy

Mathematics

2 answers:

creativ13 [48]2 years ago

6 0

In case your expression is:

$x^2\:-\:xy\:+\:x^2\:-\:xy$

Solution:

Given the expression

$x^2\:-\:xy\:+\:x^2\:-\:xy$

Group like terms

$x^2\:-\:xy\:+\:x^2\:-\:xy=x^2+x^2-xy-xy$

Add similar elements: x²+x² = 2x²

$=2x^2-xy-xy$

Add similar elements: -xy-xy = -2xy

$=2x^2-2xy$

Thus,

$x^2-xy+x^2-xy=2x^2-2xy$

In case your expression is:

$\left(xx\right)^2\:-\:xy\:+\:x^2\:-\:xy$

Solution:

Given the expression

$\left(xx\right)^2\:-\:xy\:+\:x^2\:-\:xy$

Group like terms

$\left(xx\right)^2\:-\:xy\:+\:x^2\:-\:xy=x^2-xy-xy+\left(xx\right)^2$

Add similar elements: -xy-xy = -2xy

$=x^2-2xy+\left(xx\right)^2$

as (xx)² = x⁴

so $=x^2-2xy+x^4$

Therefore, we conclude that:

$\left(xx\right)^2\:-\:xy\:+\:x^2\:-\:xy=x^2-2xy+x^4$

EastWind [94]2 years ago

4 0

Answer and Step-by-step explanation:

$x^{2} - xy + x^{2} -xy\\\\2x^{2} -2xy$

This is the answer.

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Rectangle ABCD is shown to the right. Point E is located

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A) The area of the rectangle ABCD is base times height. 20in x 12in = 240 in sq.
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3 years ago

Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

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2 years ago

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tino4ka555 [31]

"Note how for each (x,y) pair of points given we see that x*y = 60
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The fact that this is true for ALL of the points shown indicates we have an inverse variation of the form x*y = k where k = 60 in this case.
Therefore, the answer is B.) An inverse function is the best model because the products of corresponding x- and y-values are equal."

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Answer:

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Step-by-step explanation:

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Xx squared - XY + x squared - xy ​

Xx squared - XY + x squared - xy