All categories

2 years ago

Xx squared - XY + x squared - xy

Mathematics

2 answers:

creativ13 [48]2 years ago

6 0

In case your expression is:

$x^2\:-\:xy\:+\:x^2\:-\:xy$

Solution:

Given the expression

$x^2\:-\:xy\:+\:x^2\:-\:xy$

Group like terms

$x^2\:-\:xy\:+\:x^2\:-\:xy=x^2+x^2-xy-xy$

Add similar elements: x²+x² = 2x²

$=2x^2-xy-xy$

Add similar elements: -xy-xy = -2xy

$=2x^2-2xy$

Thus,

$x^2-xy+x^2-xy=2x^2-2xy$

In case your expression is:

$\left(xx\right)^2\:-\:xy\:+\:x^2\:-\:xy$

Solution:

Given the expression

$\left(xx\right)^2\:-\:xy\:+\:x^2\:-\:xy$

Group like terms

$\left(xx\right)^2\:-\:xy\:+\:x^2\:-\:xy=x^2-xy-xy+\left(xx\right)^2$

Add similar elements: -xy-xy = -2xy

$=x^2-2xy+\left(xx\right)^2$

as (xx)² = x⁴

so $=x^2-2xy+x^4$

Therefore, we conclude that:

$\left(xx\right)^2\:-\:xy\:+\:x^2\:-\:xy=x^2-2xy+x^4$

EastWind [94]2 years ago

4 0

Answer and Step-by-step explanation:

$x^{2} - xy + x^{2} -xy\\\\2x^{2} -2xy$

This is the answer.

You might be interested in

Discuss how surface area and volume play a role in marketing products, such as advantages and disadvantages. Give specific examp

lubasha [3.4K]

Big packages drives you to the illusion that the contents are bigger or better which is actually not possible.Even garbage can fill up a huge truck.
Selling something with more volume means you get more for the money. 
Advantage of marketing something as bigger helps you to get them to buy more than the usual.Its a technique to sell more items. 
Disadvantage is they don't need to come back as often to buy again.

5 0

3 years ago

Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.

Ann [662]

Note that if ${x_2}'=x_1$ , then ${x_2}''={x_1}'$ , and so we can collapse the system of ODEs into a linear ODE:

${x_2}''=3{x_2}'-x_2+e^t$
${x_2}''-3{x_2}'+x_2=e^t$

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

$r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0$

so that the characteristic solution is

${x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}$

Now let's suppose the particular solution is ${x_2}_p=ae^t$ . Then

${x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t$

and so

$ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1$

Thus the general solution for $x_2$ is

$x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t$

and you can find the solution $x_1$ by simply differentiating $x_2$ .

7 0

3 years ago

The length of a rectangle is 12 in. and the perimeter is 56 in. find the width of the rectangle

pentagon [3]

The perimeter p of the rectangle with length l and width w is:
p = 2l + 2w
that is, two times its length and two times its width, lets solve for the width w and substitute known data:
p = 2l + 2w
2w = p - 2l
w = (p - 2l)/2
w = (56 - (2*12))/2
w = (56 - 24)/2
w = 32/2
w = 16
therefore the width of the rectangle is 16 in

8 0

3 years ago

The table shows four transactions and the resulting account balance in a bank account, except some numbers are missing. Fill in

rusak2 [61]

For transaction 3 it should be -155.15 and for transaction 4 it would be -223.75

6 0

2 years ago

Write 2.452 x 10 in standard notation.

-Dominant- [34]

Answer:

24.52

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Xx squared - XY + x squared - xy ​

Xx squared - XY + x squared - xy