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Georgia [21]
3 years ago
13

the shapes below are drawn on a centimeter grid, show that the triangle and the square have the same area.

Mathematics
1 answer:
guajiro [1.7K]3 years ago
3 0

Answer:

Area_square = 4 cm2

Area_triangle = 4 cm2

Step-by-step explanation:

The first thing to do is calculate the area of both figures.

The area of the square is given by:

Area_square = side * side

The side of the square is 2 cm, so:

Area_square = 2 * 2 = 4 cm2

The area of the triangle is given by:

Area_triangle = base * height / 2

The base is 2 cm, and the height is 4 cm, so we have:

Area_triangle = 2 * 4 / 2 = 4 cm2

So we have that Area_square = Area_triangle = 4 cm2

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Anyone please help!!!
Tanya [424]

Problem 1

Answers:

Percentage of patients that were dogs = 46%

Standard Error = 0.07048404074682

Margin of error for 90% confidence interval = 0.11594624702851

Margin of error for 95% confidence interval = 0.13814871986377

Round the decimal values however you need them

------------

To get the first answer, you add up the numbers given (7,4,5,5,2) and divide that over 50. So 7+4+5+5+2 = 23 which leads to 23/50 = 0.46 = 46%; therefore phat = 0.46 is the sample proportion of dogs.

Use the SE (standard error) formula given to you with phat = 0.46 and n = 50 to get SE = 0.07048404074682

The critical z value at 90% confidence is 1.645; this value is found in your Z table (back of your stats textbook). Multiply the SE value by 1.645 to get 0.07048404074682*1.645 = 0.11594624702851

Also found in your textbook is 1.960 which is the z critical value at 95% confidence. Multiply this with the SE value to get 0.07048404074682*1.960 = 0.13814871986377

===============================================

Problem 2

Answer: Choice B) picking balls from a bin; the 60 randomly selected get chosen for the first bus, while the remaining 60 go to the second bus

-----------

Choice A is fairly vague on what the lower and upper boundaries are. What is the smallest number allowed? What about the largest? This isn't clear so it's possible that we could end up with more positive numbers than negative (eg: if we had an interval -10 < x < 110). So choice A is false. A similar issue shows up with choice D.

Choice B is true. Assuming the selection process is random and not biased, then each ball is equally likely for each selection. The fact that the balls are colored seems to be extra info which I'm not sure why your teacher threw that in there.

Choice C is false because choice B is true

Choice D is false for similar reasons as choice A. It's not clear where we start and where we end. If we had the interval 2 < x < 6 then x could take on the values {3, 4, 5} and we see that picking an odd number is twice as likely than picking an even. In this example, there is bias.

===============================================

Problem 3

Answer: Choice B) Roll a die; each number corresponds to a different class

------------

Choice A is false because choice B being the answer contradicts it

Choice B is true: there are 6 sides on the die, and each side is equally likely to be landed on, so each class is equally likely

Choice C is false because 2*2*2 = 8 represents the number of combos you can have when you flip three coins (one combo being HTH for heads tail heads) but there are 6 classes, not 8

Choice D is false because while we want 6 regions on the spinner. Each region must have the same area; otherwise, one class is weighted heavier than the others making it more likely you select that particular class.


7 0
3 years ago
Read 2 more answers
If in triangle ABC, a=5, b=6 and c=8, then cos A is...
s2008m [1.1K]

In a triangle, the nomenclature is that a variable side a is opposite of the angle A. we can use the cosine law to determine the value of cosine A. 
a2 = b2 + c2 -2bc cos a25 = 36 + 64 - 2*6*8 * cos acos a = 25/32 
5 0
4 years ago
$29,000;$4 decrease find the new amount given the original amount and the percent of change.
stellarik [79]
$1 - (28,996/29,000) = 0.000138
0.0138%
7 0
3 years ago
When truckers are on long-haul drives, their driving logs must reflect their average speed. Average speed is the total distance
KengaRu [80]

Answer:

0.500 hour

Step-by-step explanation:

Givens

<em><u>Distance</u></em>

  • Total Distance on the highway = 3hr * 60 miles / hr = 180 miles
  • Distance in the city = 20 miles
  • Total Distance = 180 + 20 = 200 miles

<em><u>Time</u></em>

  • Time on the highway = 3 hours
  • Time in the city = x

Formula

d /t = r

Solution

  • Average rate = 57.14
  • Total Distance / Total Time = average rate
  • 200 / (3 + x) = 57.14                               Multiply both sides by 3 + x
  • 200 = 57.14 * (3 + x)                               Remove the brackets
  • 200 = 57.14*3 + 57.14x                           Multiply the factors on the right
  • 200 = 171.42 + 57.14x                              Subtract 171.42 from both sides.
  • 200 - 171.42 = 171.42 - 171.42 + 57.14x   So the subtraction
  • 28.58 = 57.14x                                         Divide by 57.14
  • 28.57/57.14 = x
  • x = 0.500 hour                                        Answer


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7 0
3 years ago
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