The width of the rectangle is twice the length of the rectangle
<h3>How to compare the dimensions of the rectangle?</h3>
The given parameters are:
Width = 4 cm
Length = 2 cm
Express 4 cm as 2 * 2 cm
Width = 2 * 2 cm
Substitute Length = 2 cm in Width = 2 * 2 cm
Width = 2 * Length
This means that the width of the rectangle is twice the length of the rectangle
Hence, the true statement is that the width of the rectangle is twice the length of the rectangle
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Answer:
I believe the question says "5j + 16 - 12(-9j - 4) - 12j" I hope I'm correct because I have almost no idea what you typed.
If you did type "5j + 16 - 12(-9j - 4) - 12j" then your answer would be 133j + 52 I believe. You never put how you would like your problem to be solved, so I simplified.
Step-by-step explanation:
Hope this helps.
We know that 1 side is 100 and 1 angle is 90 degrees
we would need at least 1 more angle or 1 more side length to say that they are similar
no
but, if we asssume that DCB is a straignt line, then we can say that they are similar
2. if we say taht they are similar then DE=AB, so then 175=DE=AB
Answer:
83.74 in squared
Step-by-step explanation:
The area of the original rectangle is: 14 * 8 = 112 in squared.
The area of a circle is , where r is the radius. In this case, we know the diameter is 6, so the radius is 3. Then, the area of the circle is:
3.14 * 3^2 = 3.14 * 9 = 28.26 in squared.
The remaining area is just the total minus the circle area:
112 - 28.26 = 83.74 in squared
Answer:
We dont need pie. Pie is a option. A thing we want
Step-by-step explanation: