Question

Find the equation of the lines perpendicular and parallel to 2x-3y=8 line through the point (-2,-4)

Answer 1

Answer:

y= -1.5x-7 is the equation of the perpendicular line

Here's why:

when we convert 2x-3y=8 to standard form, we get y= 2/3x-8/3. This means the perpendicular line will have a slope of the negative reciprocal of the original one, so the perpendicular slope is -1.5. When we substitute the points (-2,-4) into the equation y=-1.5x+b, we get a b value of -7. So the perpendicular line equation is y= -1.5x-7. You can't the parallel line equation with the points (-2,-4) as it is part of the line 2x-3y=8.