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2 years ago

Find the equation of the lines perpendicular and parallel to 2x-3y=8 line through the point (-2,-4)

Mathematics

1 answer:

marysya [2.9K]2 years ago

8 0

Answer:

y= -1.5x-7 is the equation of the perpendicular line

Here's why:

when we convert 2x-3y=8 to standard form, we get y= 2/3x-8/3. This means the perpendicular line will have a slope of the negative reciprocal of the original one, so the perpendicular slope is -1.5. When we substitute the points (-2,-4) into the equation y=-1.5x+b, we get a b value of -7. So the perpendicular line equation is y= -1.5x-7. You can't the parallel line equation with the points (-2,-4) as it is part of the line 2x-3y=8.

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2 years ago

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Which statements about countries with lower GDP and lowest HDI scores are accurate?

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3 years ago

Read 2 more answers

Hi! Please help me, will mark brainliest!

PIT_PIT [208]

Answer:

p(t) = 0 for t = 1

p(t) = 1 for t = 1/8 = 8^-1

Step-by-step explanation:

the graph you will have to do yourself.

just go there and type in

$- log_{8}(x)$

well, don't type "log" in letters.

you start by typing the "-" sign, and then you need to look up the functions by clicking on the "funcs" button and look for the log functions .

pick the

$log_{a}$

option. and then simply enter 8 as the first parameter in the {} brackets and x as the second in the () brackets.

and then you see.

any logarithm is 0 for x (or t) = 1.

because any a⁰ = 1.

and the logarithm gives you that exponent of the base number that leads to the given x value.

in other words : a logarithm is the inverse function of an exponential function.

the exponential function is

y = a^x

and the logarithm then determines

$x = log_{a}(y)$

that is all.

and

$- log_{8}(x) = 1$

means that the logarithm itself delivered -1.

and 8^-1 = 1/8

so, p(t) = 1 for t = 1/8

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2 years ago