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IgorC [24]
3 years ago
15

6 • 10^2 is how many times as 3• 10^3

Mathematics
1 answer:
yarga [219]3 years ago
4 0

Answer:

.2 times because it is actually less

Step-by-step explanation:

In other words 600 is how many times as 3000

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1
gayaneshka [121]

Step-by-step explanation:

OOOO

BYE

8 0
3 years ago
An airplane descends at a rate of 500 feet per minute.Write and evaluate an expression to show how far the plane will descend in
Nataly_w [17]

Answer:

500/6 min if I'm correct

Step-by-step explanation:

8 0
3 years ago
Help please !!!!! asap
AnnyKZ [126]
The answer: m∡BCD = 130° .
_____________________________________
Explanation:
______________________________
m∡BCD = 9x - 5 = our answer.
_____________________________
Note: (9x - 5) + (m∡C IN Δ  ACB)= 180 ;
____________________________
Reason: all angles on straight line add up to 180.
___________________________
Note: In Δ ACB; m∡A + m∡B + m∡c = 180.
_________________________________________
Reason: All three angles in any triangle add up to 180.
__________________________________________
Given  Δ ACB, we are given:
_____________
m∡C= ?
m∡B = (4x + 5)
m∡A = 65
_____________________
So, given  Δ ACB; m∡A + m∡B + m∡c = 180;
 →Plug in our known values and rewrite:
___________________________________
Given  Δ ACB; 65 + 4x + 5 + (m∡c) = 180;
  →Simplify, and rewrite:
___________________________________
Given  Δ ACB; 4x + 70 + (m∡c) = 180;
  →Subtract "70" from each side of the equation; and rewrite:
___________________________________
Given  Δ ACB; 4x + (m∡C) = 110;
   →Subtract "4x" from EACH SIDE of the equation; to isolate: "(m∡c)" on one side of the equation; and "solve in terms of "(m∡C)" ;
______________________________________________
Given Δ ACB' m∡C = 110 - 4x ;
__________________________________________
So, we know that: (110 - 4x) + (9x - 5) = 180; (since all angles on a straight line add up to 180.
____________________
We can solve for "x".
____________________
(110 - 4x) + (9x - 5) = 180;
________________________
Rewrite as: 
___________
(110 - 4x) + 1(9x - 5) = 180 ;  (Note: there is an implied coefficient of "1"; since anything multiplied by "1" equals that same value).
_______________________
Note the "distributive property of multiplication": 
_________________
 a*(b+c) = ab + ac ; AND:
 a*(b - c) = ab - ac .
_______________________
So, +1(9x - 5) = (+1*9x) - (+1*5) = 9x - 5 ;
__________________________
So we can rewrite:
___________________
(110 - 4x) + (9x - 5) = 180 ; as:
________________________
110 - 4x + 9x - 5 = 180 ;  We can simplify this by combining "like terms" on                                         the "left-hand side" of the equation:
_________________________________________________
110 - 5 = 105 ;
-4x + 9x = 5x; 
______________
So, rewrite as: 5x + 105 = 180;  Subtract "105" from EACH side; to get:
_____________________________________
 5x  = 75 ; Now, divide each side of the equation by "5"; 
              to get: x = 15.
_____________________________________________
Now, we want to know: m∡BCD; which equals:
_____________________________________________
 9x - 5 ;  let us substitute "15" for "x"; and solve:
______________________
9x - 5 = 9*(15) - 5 = 135 - 5 = 130.
_____________________________
The answer: m∡BCD = 130°
________________________
6 0
3 years ago
Help me you guys I will apprecaite
stepladder [879]
I think your answer would be 14 if this is what it’s asking for
Because 6/6 makes 1 so 13+1 is 14
6 0
3 years ago
How many 'words' can be made from the name ESTABROK with no restrictions
Bumek [7]

The number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.

<h3>How to determine the number of ways</h3>

Given the word:

ESTABROK

Then n = 8

p = 6

The formula for permutation without restrictions

P = n! ( n - p + 1)!

P = 8! ( 8 - 6 + 1) !

P = 8! (8 - 7)!

P = 8! (1)!

P = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 × 1

P = 40, 320 ways

Thus, the number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.

Learn more about permutation here:

brainly.com/question/4658834

#SPJ1

6 0
1 year ago
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