Answer:
C.) 35.08 is the answer
Step-by-step explanation:
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<u>Question</u>
Suppose that a committee is studying whether or not there is excessive time waste in our judicial system. It is interested in the mean amount of time individuals spend at the courthouse waiting to be called for jury duty. The committee randomly surveyed 81 people who recently served as jurors. The sample mean wait time was 4 hours with a sample standard deviation of 1.2 hours. Define the random variables X and in words.
Answer:
(B)
- X is the amount of time an individual waits at the courthouse to be called for service.
- is the mean wait time for a sample of individuals.
Step-by-step explanation:
The random variable X is the amount of time for which each of the prospective juror waits at the courthouse before being called for service.
is the mean wait time for a the given sample of individuals. In the case given,
Answer:
11
Step-by-step explanation:
The distance that a is to b is b-a=17-2=15.
The line segment from a=2 to b=17 has length 15.
We need to know what is 3/5 of 15.
3/5 of 15 means what is 3/5 times 15?
(3/5)(15)=3(3)=9
So this means we are looking to make a line segment that is 9 units from 2 which is 2 to 11.
So 11 is 3/5 the way from a=2 to b=17.
Let's check from 2 to 11 that is a length of 9 and from 2 to 17 that is a length of 15.
Is 9/15 equal to 3/5?
Yes, 9/15 can be reduced to 3/5.
Answer 420.
a, is the first term. d is difference.
Since this is an arithmetic progression, I use this formula.
Un = nth term
Sn = sum of terms.
First find the number of terms, which is 20.
Then use the second formula to find the sum.
Angles ECD and CEF add to 180
40+140 = 180
So that means we have EF parallel to CD (due to the same side interior angle theorem)
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Angles BCE and ECD combine to 30+40 = 70, which is congruent to angle ABC = 70 as well.
In other words, this shows angle ABC = angle BCD. Both of these angles are alternate interior angles. Since they're congruent, they lead to AB being parallel to CD.
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So far we have
AB || CD
CD || EF
Using the transitive property, we can then link the two statements to say AB || EF. Think of a chain where CD is the common link. We go from AB to CD, then from CD to EF. So we can just take a single path from AB to EF.
It's like saying "P --> Q and Q --> R, therefore P --> R"