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1 year ago

What integer values satisfy both inequalities? − 3 < x < 2 x > − 1

Mathematics

1 answer:

anzhelika [568]1 year ago

5 0

Answer:

its 1!

Step-by-step explanation:

1 is greater than -3, and 2*1 (2) is greater than -1 :)

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Choose the equation below that represents the line passing through the point (-3,-1) with a slope of 4.

Bingel [31]

Y = mx + b
slope(m) = 4
(-3,-1)...x = -3 and y = -1
now we sub...we r looking for b, the y int.
-1 = 4(-3) + b
-1 = -12 + b
-1 + 12 = b
11 = b

so ur equation is : y = 4x + 11

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3 years ago

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Irina-Kira [14]

I think it’s 0.85d, but i’m not sure

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3 years ago

Given: PRST is a square

xxTIMURxx [149]

Answer:

$(1-\sqrt{2})a^2$

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

$PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a$

Thus,

$MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a$

Consider isosceles triangle MSC. In this triangle

$MS=MC=(\sqrt{2}-1)a.$

The area of this triangle is

$A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}$

Consider right triangle PTS. The area of this triangle is

$A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}$

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

$A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2$

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3 years ago

A marble factory makes single marbles, then put them in boxes of 10, cartons of 100 and crates of 1,000. How can the marble fact

Luba_88 [7]

21 crates, 6 cartons, 5 boxes

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3 years ago

16% of a number is 60. What is that number? A375 B 432 C 456 D753

Vlad1618 [11]

Answer:

Its A: 375

Because, if you take 26.6 you have to round it. So, the 6 behind the decimal is over 5 so make the other 6 in front of the decimal a 7. So, the 7 will add 1 to the 2 to make it 3. And i forgot how to get the 5, but trust me dis is right. :3

4 0

3 years ago