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3 years ago

Which solution value satisfies the inequality x + 10 > 12?

Mathematics

1 answer:

prisoha [69]3 years ago

8 0

Answer:

A) x=3

Step-by-step explanation:

As for B, C, and D,

if x=-1, 9>12 is not true,

if x=0, 10>12 is not true

if x=2, 12>12 is not true

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Ede4ka [16]

Answer:

Step-by-step explanation:

$a = b \times h \\ \\ a = 9 \: \: {yd}^{2} \\ b = 6 \: \: yd \\ \\ 9 = 6 \times h \\ h = \frac{9}{6} \\ h = 1.5 \: \: yd$

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3 years ago

Select the correct answer

Tomtit [17]

Answer:

Step-by-step explanation:

The area for a triangle is

$A=\frac{1}{2}bh$

Our base is given as x, the height is given as 1 more than 6 times the base which looks like this: 6x + 1. We know that the area is 13, so filling in everything:

$13=\frac{1}{2} (6x+1)(x)$

We can get rid of the denominator of 2 by multiplying it on both sides to get:

$26=(6x+1)(x)$ and simplifying a bit:

$26=6x^2+x$

Now we can move over the 26 and put the expression into standard quadratic form by setting it equal to 0:

$6x^2+x-26=0$ which is choice C

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2 years ago

Which account is an example of a contra-revenue account?

sleet_krkn [62]

A contra revenue account might be described as a revenue account that is expected to have a debit balance instead of the usual credit balance

So the answer is sales discount

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3 years ago

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Mkey [24]

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2 years ago

Read 2 more answers

A rectangle is 12cm longer than its wide. It's perimeter is 68m, how do you find it's length and width?

Zina [86]

Answer:

Width: 1694 cm or 16.94 m

Length: 1706 cm or 17.06 m

Step-by-step explanation:

1. Write out the known equations:

First, the equation for the perimeter of a rectangle:

$Perimeter = 2(Width) + 2(Length)$

We also know that the rectangle is 12 cm longer than it is wide. This leads to the second equation:

$Length=Width+12$

2. Solve the system of equations for width:

Since we know the length in terms of width, and we know the perimeter, we can plug these values into the equation for the perimeter. First, let's rearrange the equation for perimeter to solve for width:

$Perimeter = 2(Width) + 2(Length)\\Perimeter-2(Length)=2(Width)\\2(Width)=Perimeter-2(Length)\\Width=\frac{Perimeter-2(Length)}{2}$

Now, plug in the known values (since there are 100 cm in one metre, I'm multiplying the perimeter of 68 m by 100 to convert to centimetres--the perimeter of 68 m is equal to 6800 cm):

$Width=\frac{6800-2(Width+12)}{2}$

Now, solve the equation for width:

$Width=\frac{6800-2(Width+12)}{2}\\2(Width)=6800-2(Width+12)\\2(Width)=6800-2(Width)-24\\2(Width)+2(Width)=6800-24\\4(Width)=6800-24\\4(Width)=6776\\Width=1694cm$

3. Solve for length using width:

Now that we know the width, we can easily solve for the length using our previously established equation for length, $Length=Width+12$ , as shown:

$Length=Width+12\\Length=1694+12\\Length=1706cm$

4. Convert to metres.

If you want to know the answer in metres, you can convert from centimetres by dividing by 100:

1694/100 = 16.94 m

1706/100 = 17.06 m

4 0

2 years ago