All categories

3 years ago

Which solution value satisfies the inequality x + 10 > 12?

Mathematics

1 answer:

prisoha [69]3 years ago

8 0

Answer:

A) x=3

Step-by-step explanation:

As for B, C, and D,

if x=-1, 9>12 is not true,

if x=0, 10>12 is not true

if x=2, 12>12 is not true

You might be interested in

How do you figure this out?

podryga [215]

$2x^2-4x-6=0\\ x^2-2x-3=0\\ x^2+x-3x-3=0\\ x(x+1)-3(x+1)=0\\ (x-3)(x+1)=0\\ x=3 \vee x=-1$

8 0

4 years ago

Read 2 more answers

akiko's dog has three puppies they weigh 2.6 pounds 2.74 pounds and 3.1 pounds how much more does the heaviest puppy weigh than

dsp73

3.1 - 2.6 = 0.5 pounds

4 0

3 years ago

Read 2 more answers

W= x/y-x solve for x

svetoff [14.1K]

Answer: w=−xy+x/y

Step-by-step explanation:

Let's solve for w.

−x

Step 1: Multiply both sides by y.

wy=−xy+x

Step 2: Divide both sides by y.

−xy+x

3 0

3 years ago

Which expressions are equivalent to -6+4q+(-6q)

nlexa [21]

Answer:

-2 (q + 3)

Step-by-step explanation:

Simplify the following:

-6 + 4 q - 6 q

Grouping like terms, -6 + 4 q - 6 q = (4 q - 6 q) - 6:

(4 q - 6 q) - 6

4 q - 6 q = -2 q:

-2 q - 6

Factor -2 out of -2 q - 6:

Answer: -2 (q + 3)

3 0

4 years ago

Read 2 more answers

Results of a survey conducted in 15 large cities within the U.S. finds that the average commute time one way to/from work is 25.

irina1246 [14]

Answer:

We conclude that commute time in her city is less than the amount reported by the survey which is 25.4 minutes.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 25.4 minutes

Sample mean, $\bar{x}$ = 22.1 minutes

Sample size, n = 15

Alpha, α = 0.10

Sample standard deviation, s = 5.3 minutes

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 25.4\text{ minutes}\\H_A: \mu < 25.4\text{ minutes}$

We use one-tailed t(left) test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{22.1 - 25.4}{\frac{5.3}{\sqrt{15}} } = -2.411$

Now, $t_{critical} \text{ at 0.10 level of significance, 14 degree of freedom } = -1.345$

Since,

$t_{stat} < t_{critical}$

We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

Thus, there is enough evidence to conclude that commute time in her city is less than the amount reported by the survey which is 25.4 minutes.

7 0

4 years ago