Answer:
a) 1.3652
b) 1.3906
Step-by-step explanation:
a) log5 9 = log5 3² = 2log5 3 = 2(0.6826) = 1.3652
b) log5 75/8 = log5 75 - log5 8 = log5 3×25 - log5 8=
log5 3 + log5 5² - log5 8 = 0.6826 + 2 - 1.2920 = 0.6826 + 0.708 = 1.3906
Answer:
Step-by-step explanation:
Yes, this distance will be different depends on the car, exactly the car's motor, we could have the same gasoline litter but if we have a car with a small motor the gasoline would last longer.
For example:
A small car could travel more miles than a big car with a v6 motor, a small car could use 4 litter in an hour, in a truck could use 8 litter or more in an hour depends on the motor, assuming we traveled 24.2 miles per hour.
Answer:
Welcome ganger
Step-by-step explanation:
Answer:
They'll meet after 200 meters , if they simultaneously start running towards each other.
Step-by-step explanation:
Let x =distance travelled by dog and 200-x be the distance travelled by cat. Inorder to meet, the sum of their travelled distances shall be equal to 200 meters as they are far apart by 200 meters.
Dog: Distance =Speed x time: x=30t
Cat: Distance = 200-x
=24t
The sum of their distance travelled shall be 200 meters: 30t+ 24t= 200;54t=200;t=200/54=3.7secs
So they will meet after 3.7 seconds
To check:
Distance travelled by dog :x=30(3.7)
=111.11 meters
Distance travelled by cat: 24t=24(3.7)
=88.89 meters
Therefore since they are travelling towards each other and their distance apart is 200 meters, after 3.7 seconds they will meet because dog travelled 111.11 meters and cat travelled 88.89 meters and they covered already 200 meters as the sum of 111.11+ 88.89
=200 meters
