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Finger [1]
2 years ago
8

SOMEONE PLEASE HELP ME WITH THIS KHAN ACADEMY ASSIGNMENT ASAP

Mathematics
1 answer:
Alchen [17]2 years ago
4 0

Answer:

(8,-4)

Step-by-step explanation:

The difference between A and M is 2.5x and -4y

so B would be 5.5+2.5 and 0-4

(8,-4)

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The components of vector A are (10.5, 10.2). Waht is the magnitude of the vector?
Nataly_w [17]

Answer:

||\overrightarrow{v}||\approx14.64

Step-by-step explanation:

The magnitude of a vector \displaystyle \overrightarrow{v}=\langle x,y\rangle is ||\overrightarrow{v}||=\sqrt{x^2+y^2}, which essentially describes the length of the vector itself between the initial and terminal points:

||\overrightarrow{v}||=\sqrt{x^2+y^2}\\\\||\overrightarrow{v}||=\sqrt{(10.5)^2+(10.2)^2}\\\\||\overrightarrow{v}||=\sqrt{110.25+104.04}\\\\||\overrightarrow{v}||=\sqrt{214.29}\\\\||\overrightarrow{v}||\approx14.64

6 0
2 years ago
19)
lesantik [10]
It would be answer D your welcome
3 0
3 years ago
Read 2 more answers
X + 14 = 56 What would I do to both sides to answer this equation? O Multiply both sides by 14 © Subtract both sides by 14 Subtr
Lorico [155]

To solve for X in this equation, you would subtract both sides by 14 because our goal is to get X on its own. If we write it out, we see that

X + 14 - 14 = 56 - 14

X=42

Because we have a positive 14, a negative 14 will average out to be 0, but what you do to one side, you must do to the other.

If you have any more questions, feel free to ask!

8 0
3 years ago
Plz Help <br> A. Yes<br> B. No<br> c. Maybe<br> D. Can4 be determined
mixer [17]
This answer is C i did this once
6 0
2 years ago
Read 2 more answers
What is the GCF of 44j5k4 and 121j2k6?<br><br> 4j3k2<br> 4j2k4<br> 11j3k2<br> 11j2k4
egoroff_w [7]

Answer:

D) 11j2k4

Step-by-step explanation:

Simply find the prime factors of each term!

44 j5 k4

121 j2 k6

11 goes into 44 and 121. So, we can use 11!

2 works for j5 and j2, because of 10, so you would input j2.

4 works for both k4 and 46 because of 24, so k4.

11 j2 k4

Hope this helps! :)

5 0
3 years ago
Read 2 more answers
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