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4 years ago

D is the midpoint of CE. C has coordinates

Mathematics

1 answer:

tiny-mole [99]4 years ago

4 0

Answer:

you need to be more specific like which ones are x or y

Step-by-step explanation:

ask it again or comment the specifics

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What is a ratio that compares a number to 100?

Aleks04 [339]

1:100 could be an example of a ratio comparing to 100

3 0

4 years ago

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Suppose you loan $320 to a friend and charge them 11% annual interest. If they don't pay you back, how much will they owe you af

RSB [31]

Answer:

Step-by-step explanation:

You want to calculate the interest on $320 at 11% interest per year after 5 year(s).

The formula we'll use for this is the simple interest formula, or:

Where:

P is the principal amount, $320.00.

r is the interest rate, 11% per year, or in decimal form, 11/100=0.11.

t is the time involved, 5....year(s) time periods.

So, t is 5....year time periods.

To find the simple interest, we multiply 320 × 0.11 × 5 to get that:

The interest is: $176.00

Usually now, the interest is added onto the principal to figure some new amount after 5 year(s),

or 320.00 + 176.00 = 496.00. For example:

If you borrowed the $320.00, you would now owe $496.00

If you loaned someone $320.00, you would now be due $496.00

8 0

3 years ago

I don’t know how to solve this

Lady_Fox [76]

Answer:

$\theta =2\pi k,\ \ k\in Z\ \\\text{or}\ \\\theta=-\dfrac{2\pi}{3}+2\pi k,\ \ k\in Z$

Step-by-step explanation:

Given:

$\cos \theta-\sqrt{3}\sin \theta=1$

Divide this equation by 2:

$\dfrac{1}{2}\cos \theta-\dfrac{\sqrt{3}}{2}\sin \theta=\dfrac{1}{2}$

Note that

$\cos \dfrac{\pi }{3}=\dfrac{1}{2}\\ \\\sin \dfrac{\pi }{3}=\dfrac{\sqrt{3}}{2}$

So, the previous equation is

$\cos \dfrac{\pi}{3}\cdot \cos \theta-\sin \dfrac{\pi}{3}\cdot \sin \theta=\dfrac{1}{2}$

Remind that

$\cos x\cos y-\sin x\sin y=\cos (x+y),$

then

$\cos \left(\dfrac{\pi}{3}+\theta\right)=\dfrac{1}{2}$

The solution of this equation is

$\dfrac{\pi}{3}+\theta=\pm \arccos \dfrac{1}{2}+2\pi k,\ \ k\in Z\\ \\\dfrac{\pi}{3}+\theta=\pm \dfrac{\pi}{3}+2\pi k,\ \ k\in Z\\ \\\theta =2\pi k,\ \ k\in Z\ \text{or}\ \theta=-\dfrac{2\pi}{3}+2\pi k,\ \ k\in Z$

8 0

3 years ago

PLEASE HELP! Fill in the blank!<br> 5 - _ = 14

pochemuha

-8

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

OMG i'm freaking out. I take 8th grade algebra and my parents don't understand this. I need help! Can someone explain these two

Ivan

Sure, can I see the problem?

6 0

3 years ago