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Savatey [412]
3 years ago
9

D is the midpoint of CE. C has coordinates

Mathematics
1 answer:
tiny-mole [99]3 years ago
4 0

Answer:

you need to be more specific like which ones are x or y

Step-by-step explanation:

ask it again or comment the specifics

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A line passes through the points (-6, -3)and (6,-3) which of the following points is also on the line
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SEND YOUR LOCATION COME THROUGH  you a rear breed no comparing

Step-by-step explanation:

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A regular polygon is a polygon with blank sides and angles
In-s [12.5K]
Regular polygon is a polygon with equal sides and equal angles!!!
5 0
3 years ago
The president of a small manufacturing firm is concerned about the continual increase in manufacturing costs over the past sever
mrs_skeptik [129]

Answer:

The answers to the question are

(a) The time series plot is given as attached

(b) The parameters for the line that minimizes MSE for the time series are;

y-intercept, b₀ = 19.993

Slope, b₁ =  1.77

MSE = 19.44

T_t = 19.993  + 1.774·t

(c) The average cost increase that the firm is realizing per year is $ 1.77

(d) The estimate of the cost/unit for next year is $35.96.

Step-by-step explanation:

(a) Using the provided data, the time series plot is given as attached

(b) Given hat the y-intercept, = b₀

Slope = b₁

Therefore the  linear trend forecast equation is given s

T_t = b₀ + b₁·t

The linear trend line slope is given as

b₁ = \frac{\Sigma^n_{t=1}(t-\overline{\rm t)}(Y_t-\overline{\rm Y)}}{\Sigma^n_{t=1}(t-\overline{\rm t} )^2}

b₀ = \overline{\rm Y} - b₁·\overline{\rm t}

Where:

Y_t = Time series plot value at t

n =  Time period number

\overline{\rm Y} = Time series data average value and

\overline{\rm t} = Average time, t

Therefore, \overline{\rm t} = \frac{\Sigma^n _{t=1} t}{n}  = \frac{36}{8} =4.5

\overline{\rm t} = 4.5

\overline{\rm Y}  =  \frac{\Sigma^n _{t=1} Y_t}{n}  = \frac{223.8}{8} =27.975

\overline{\rm Y}  =  27.975

Therefore the linear trend line equation T_t, is

b₁ = \frac{\Sigma^n_{t=1}(t-\overline{\rm t)}(Y_t-\overline{\rm Y)}}{\Sigma^n_{t=1}(t-\overline{\rm t} )^2} =  = \frac{74.5}{42} = 1.774

b₀ = \overline{\rm Y} - b₁·\overline{\rm t} = 27.975 - 1.774×4.5 = 19.993

Therefore the trend equation for the linear trend is

T_t = 19.993  + 1.774·t

MSE = \frac{1}{2} \Sigma(Y-\overline{\rm Y)^ }^2 = \frac{155.495}{8} = 19.44

(c) From the linear trend equation, the average is given as the slope of the curve or b₁ which is equal to 1.774

Therefore the average cost increase that the firm has been realizing per year is $ 1.77

(b) From the equation of the future trend, we have when y = 9

T_t  is given as

T_t = 19.993  + 1.774×9 = 35.96

The cost/unit for 9th year is $35.96

3 0
4 years ago
The graph of a quadratic function f has zeros of -8 and 4 and a maximum at (-2,18). What is the value of a in the function’s equ
Harrizon [31]
<h3>Answer: C) -1/2</h3>

==================================

Work Shown:

We will use the general vertex form y = a(x-h)^2+k

(h,k) is the vertex, and the 'a' value stretches or compresses the graph vertically

(h,k) = (-2,18) since the highest point is at (-2,18)

Use either root -8 or 4 to plug into the equation as well. I'll use -8

The root -8 means the point (-8,0) is an x intercept.

----------------

Plug the values mentioned into the equation below. Then solve for 'a'.

y = a(x-h)^2+k

y = a(x-(-2))^2+18 ... plug in (h,k) = (-2,18)

y = a(x+2)^2+18

0 = a(-8+2)^2+18 ... plug in (x,y) = (-8,0)

0 = a(-6)^2+18

0 = a*36+18

0 = 36a+18

36a+18 = 0

36a = -18 ... subtract 18 from both sides

a = -18/36 .... divide both sides by 36

a = (-1*18)/(2*18)

<h3>a = -1/2</h3>

---------------

Alternatively, you could use (x,y) = (4,0), instead of (x,y) = (-8,0), and you'll get the same 'a' value as well.  

7 0
4 years ago
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ivanzaharov [21]

Answer:

1/2, 7/11, 3/4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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