Answer:
1. sum of term = 465
2. nth term of the AP = 30n - 10
Step-by-step explanation:
1. The sum of all natural number from 1 to 30 can be computed as follows. The first term a = 1 and the common difference d = 1 . Therefore
sum of term = n/2(a + l)
where
a = 1
l = last term = 30
n = number of term
sum of term = 30/2(1 + 30)
sum of term = 15(31)
sum of term = 465
2.The nth term of the sequence can be gotten below. The sequence is 20, 50, 80 ......
The first term which is a is equals to 20. The common difference is 50 - 20 or 80 - 50 = 30. Therefore;
a = 20
d = 30
nth term of an AP = a + (n - 1)d
nth term of an AP = 20 + (n - 1)30
nth term of an AP = 20 + 30n - 30
nth term of the AP = 30n - 10
The nth term formula can be used to find the next term progressively. where n = number of term
The sequence will be 20, 50, 80, 110, 140, 170, 200..............
Answer: ounces
Step-by-step explanation:
Answer/Step-by-step explanation:
27.
✔️Sin 23 = opp/hyp
Sin 23 = t/34
34*sin 23 = t
t = 13.3
✔️Cos 23 = adj/hyp
Cos 23 = s/34
s = 34*cos 23
s = 31.3
28.
✔️Sin 36 = opp/hyp
Sin 36 = s/5
s = 5*sin 36
s = 2.9
✔️Cos 36 = adj/hyp
Cos 36 = r/5
r = 5*cos 36
r = 4.0
29.
✔️Sin 70 = opp/hyp
Sin 70 = w/10
w = 10*sin 70
w = 9.4
✔️Cos 70 = adj/hyp
Cos 70 = v/10
v = 10*cos 70
v = 3.4
we are given
Since, we have to solve for m
so, we will try to isolate m on anyone side
so, firstly , we will get rid of 1/6
so, we can multiply both sides by 6
now, we can simplify right side
now, we can multiply them
and we get
...........Answer
