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oksano4ka [1.4K]
3 years ago
10

Htdtdeyt5ey5jed6yyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuurrrrrrrrrrrrrrrrrrrrrrrrrr

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Mathematics
1 answer:
raketka [301]3 years ago
8 0

Answer: ok LOL thx XD

Step-by-step explanation: BRAINLIEST PLS

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Consider the exponential functions below.
klio [65]

The functions in order from least to greatest according to their average rates of change are function f at the interval [1,2], function h at the interval [0,2] and function g at the interval [2,3]

<h3>How to order the functions?</h3>

The rate of change is calculated using:

m = \frac{y_2 -y_1}{x_2 -x_1}

For function g at the interval [2,3], we have:

m = \frac{g(3) - g(2)}{3- 2}

This gives

m = \frac{20 - 4}{3- 2}

m =16

For function h at the interval [0,2], we have:

m = \frac{h(2) - h(0)}{2- 0}

Where:

h(2) = 3(3)^2 - 9 = 18

h(0) = 3(3)^0 - 9 = -6

This gives

m = \frac{18 + 6}{2 - 0}

m = 12

For function f at the interval [1,2], we have:

m = \frac{f(2) - f(1)}{2- 1}

This gives

m = \frac{12 - 6}{2 - 1}

m = 6

Hence, the functions are function f at the interval [1,2], function h at the interval [0,2] and function g at the interval [2,3]

Read more about average rates of change at:

brainly.com/question/8728504

#SPJ1

3 0
2 years ago
There are 6 circles arid 9 squares. What is the simplest ratio of circles to squares?<br> PLS HELP
lina2011 [118]

Answer:

1:2

Step-by-step explanation:

6:9 can be simplified to

divide by 3 to get simplest form

1:2

4 0
3 years ago
What is the scale factor of ALMN TO AOPO?
pochemuha

Answer:

There is a scale factor of 1

Step-by-step explanation:

the ratio 1:1 means that there is no difference between the two triangles, and that they are congruent.

4 0
3 years ago
Read 2 more answers
A swimming pool whose volume is 10 comma 000 gal contains water that is 0.03​% chlorine. Starting at tequals​0, city water conta
Katarina [22]

Answer:

C(60) = 2.7*10⁻⁴

t = 1870.72 s

Step-by-step explanation:

Let x(t) be the amount of chlorine in the pool at time t. Then the concentration of chlorine is  

C(t) = 3*10⁻⁴*x(t).

The input rate is 6*(0.001/100) = 6*10⁻⁵.

The output rate is 6*C(t) = 6*(3*10⁻⁴*x(t)) = 18*10⁻⁴*x(t)

The initial condition is x(0) = C(0)*10⁴/3 = (0.03/100)*10⁴/3 = 1.

The problem is to find C(60) in percents and to find t such that 3*10⁻⁴*x(t) = 0.002/100.  

Remember, 1 h = 60 minutes. The initial value problem is  

dx/dt= 6*10⁻⁵ - 18*10⁻⁴x =  - 6* 10⁻⁴*(3x - 10⁻¹)               x(0) = 1.

The equation is separable. It can be rewritten as dx/(3x - 10⁻¹) = -6*10⁻⁴dt.

The integration of both sides gives us  

Ln |3x - 0.1| / 3 = -6*10⁻⁴*t + C    or    |3x - 0.1| = e∧(3C)*e∧(-18*10⁻⁴t).  

Therefore, 3x - 0.1 = C₁*e∧(-18*10⁻⁴t).

Plug in the initial condition t = 0, x = 1 to obtain C₁ = 2.9.

Thus the solution to the IVP is

x(t) = (1/3)(2.9*e∧(-18*10⁻⁴t)+0.1)

then  

C(t) = 3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴t)+0.1)

If  t = 60

We have

C(60) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴*60)+0.1) = 2.7*10⁻⁴

Now, we obtain t such that 3*10⁻⁴*x(t) = 2*10⁻⁵

3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 2*10⁻⁵

t = 1870.72 s

7 0
3 years ago
Using (x + a) (x + b) = x² + (a + b) x + ab, evaluate 75 x 77
Gre4nikov [31]

(x + a) (x + b) = x² + (a + b) x + ab

75 * 77=

=(70+5)(70+7)

=70²+(5+7)*70+5*7

=4900+12*70+35

=4900+840+35

=5775

4 0
3 years ago
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