Answer:
Numbers greater than or equal to 0.
Step-by-step explanation:
The domain of this function is {x∈R | x≥0}, meaning that x can be anything greater than or equal to 0.
Answer:
Plug in your variables value.
Step-by-step explanation:
For your case, plug in -6 into the y slot
12(5+2y)= -(6-9y) +4y
12(5+2x-6)= -(6-9x-6)+4y see if that works!
Answer:
B. 12
Step-by-step explanation:
✔️Find the value of x
The side lengths of two similar triangles are always proportional.
Given that ∆ABC ~ ∆LMN, therefore:
AB = 5
LM = 10
AC = x + 5
LN = 3x + 3
Plug in the values
Cross multiply
(distributive property)
Collect like terms
Divide both sides by 5
x = 7
✔️Find AC
AC = x + 5
Plug in the value of x
AC = 7 + 5
AC = 12
Answer:
(x*9)+3=7
Step-by-step explanation:
three more is +3
product of a number and 9 is x*9
and equal to seven is =7
Answer:β=√10 or 3.16 (rounded to 2 decimal places)
Step-by-step explanation:
To find the value of β :
- we will differentiate the y(x) equation twice to get a second order differential equation.
- We compare our second order differential equation with the Second order differential equation specified in the problem to get the value of β
y(x)=c1cosβx+c2sinβx
we use the derivative of a sum rule to differentiate since we have an addition sign in our equation.
Also when differentiating Cosβx and Sinβx we should note that this involves function of a function. so we will differentiate βx in each case and multiply with the differential of c1cosx and c2sinx respectively.
lastly the differential of sinx= cosx and for cosx = -sinx.
Knowing all these we can proceed to solving the problem.
y=c1cosβx+c2sinβx
y'= β×c1×-sinβx+β×c2×cosβx
y'=-c1βsinβx+c2βcosβx
y''=β×-c1β×cosβx + (β×c2β×-sinβx)
y''= -c1β²cosβx -c2β²sinβx
factorize -β²
y''= -β²(c1cosβx +c2sinβx)
y(x)=c1cosβx+c2sinβx
therefore y'' = -β²y
y''+β²y=0
now we compare this with the second order D.E provided in the question
y''+10y=0
this means that β²y=10y
β²=10
B=√10 or 3.16(2 d.p)
