Answer:
40 minutes.
Step-by-step explanation:
- time spent on the thread mill as a function of d(day) = t(d)
= 30 +2(d-1) minutes
[where d represents day number]
(when d is 1 the time spent should be 30
so substitute d=1 and check it will be 30 only.
on first day he will spend 30 minutes so, I added 30 .
and on every additional day( these additional days are excluding first day), he will increase the time by 2 minutes.so, I added 2(d-1) to initial 30 minutes)
- so, T(6), the minutes he will spend on the treadmill on day 6=
=30+2(6-1)
=30+2(5)
=30+10
=40 minutes
(goh)(x) = (g(x))(h(x)) = (x^2)(x-7) = x^3 -7x^2
then (goh)(5) = (5^3)-7(5)^2 = 124-7(25) = 124-175 = -51
Answer:
W
PM^2 − WP(M−S)^2=T
Step-by-step explanation:
this is what mathaway said
Answer:44y=44y
Step-by-step explanation: combine the like terms of 32y and 12y and u get 44y=44y which cant be simplified further
