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2 years ago

7

I need with geometry, I need the blank spaces, anything is appreciated!

2 answers:

velikii [3]2 years ago

8 0

Answer:

2: 139

3: 139

4:41

frosja888 [35]2 years ago

5 0

Answer:

Step-by-step explanation:

10) ∠2 + 41 = 180 {Linear pair}

∠2 = 180 - 41

∠2 = 139

11) ∠3 = ∠2 {Vertically opposite angles}

∠3 = 139

12) ∠4 = 41 {Vertically opposite angles}

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2 years ago

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Step-by-step explanation:

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4 0

2 years ago

Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; $(x^2-4)^2y'' + (x + 2)y' + 7y = 0$

The above equation can be better expressed as:

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This implies that:

$p(x) = \dfrac{(x+2)}{(x^2-4)^2} \$

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$q(x) = \dfrac{7}{(x+2)^2(x-2)^2}$

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

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$\lim \limits_{x \to-2} (x+ 2) p(x) = \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{1}{(x-2)^2}$

$\implies \dfrac{1}{16}$

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Hence, one (1) of them is non-analytical at x = 2.

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2 years ago

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Ipatiy [6.2K]

Answer:

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