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Lelechka [254]
3 years ago
8

Please answer this & will mark brainliest

Mathematics
1 answer:
zvonat [6]3 years ago
8 0

Answer:

the first 1

Step-by-step explanation:

Im pretty sure

You might be interested in
The height of a triangle is 8 cm more than the base. If the area is 24 cm2, find the height and base of the triangle.
Elden [556K]

Answer:

height = 12 cm

base length = 4 cm

Step-by-step explanation:

area of a triangle

base length × height / 2

x = height

y = base length

x = y + 8

24 = y × (y + 8) / 2

48 = y × (y + 8) = y² + 8y

squared equation

y² + 8y - 48 = 0

solution

y = (-b ± sqrt(b² - 4ac))/(2a)

a = 1

b = 8

c = -48

y = (-8 ± sqrt(64 - 4×-48))/2 = (-8 ± sqrt(64 + 192))/2 =

= (-8 ± sqrt(256))/2 = (-8 ± 16)/2 = -4 ± 8

y1 = -4 + 8 = 4 cm

y2 = -4 - 8 = -12

but a negative base length did not make any sense, so only y = 4 remains.

x = y + 8 = 4 + 8 = 12 cm

5 0
3 years ago
The diameter of a circle is 6 ft. Find its area to the nearest tenth
postnew [5]

Answer:

6 rounds up to 10.

Step-by-step explanation: Please brainliest!

3 0
3 years ago
A rectangular swimming pool is 8 ft deep. One side of the pool is 4.5 times longer than the other. The amount of water needed to
AysviL [449]

Answer:

<h2> length= 42, width=12, depth=8</h2>

Step-by-step explenation:

8 0
3 years ago
HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP
Arlecino [84]

Step-by-step explanation:

try to factor them anx than set each bracket to 0 the negative one would not work

4 0
3 years ago
The function f(x) = 2x2 + 3x + 5, when evaluated, gives a value of 19. What is the function’s input value?
goldenfox [79]
f(x)=\quad 2{ x }^{ 2 }+3x+5

Let's called the input 'z'

When we plug 'z' in the function we get ;

f(z)=\quad 2{ z }^{ 2 }+3z+5

And we know that, this is equal to 19, so ;

2{ z }^{ 2 }+3z+5=\quad 19

Let's rearrange the equation.

2{ z }^{ 2 }+3z+5=\quad 19\\ \\ 2{ z }^{ 2 }+3z=\quad 19-5\\ \\ 2{ z }^{ 2 }+3z=\quad 14\\ \\ 2{ z }^{ 2 }+3z-14=\quad 0

So we have a quadratic equation here.

We'll use this formula to solve it :

\frac { -b\pm \sqrt { { b }^{ 2 }-4ac }  }{ 2a }

The formula is used in equation formed like this :

a{ x }^{ 2 }+bx+c=0

In our equation,

a=2 , b=3 and c=-14

Let's plug in the values in the formula to solve,

a=2\quad b=3\quad c=-14\\ \\ \frac { -3\pm \sqrt { 9-(4\cdot 2\cdot -14) }  }{ 4 } \\ \\ \frac { -3\pm \sqrt { 9-(-112) }  }{ 4 } \\ \\ \frac { -3\pm \sqrt { 9+112 }  }{ 4 } \\ \\ \frac { -3\pm \sqrt { 121 }  }{ 4 } \\ \\ \frac { -3\pm 11 }{ 4 }

So,

z=\quad \frac { -3+11 }{ 4 } \quad ,\quad \frac { -3-11 }{ 4 } \\ \\ z=\quad \frac { 8 }{ 4 } \quad ,\quad \frac { -14 }{ 4 } \\ \\ z=\quad 2,\quad -\frac { 7 }{ 2 }

So the input can be both, 2 and -\frac{7}{2}

8 0
3 years ago
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