Step-by-step explanation:
The statement in the above question is True.
Sum of three prime numbers (other than two) is always odd.
Going by Christian Goldbach number theory ,
- Goldbach stated that every odd whole number greater than 5 can be written as sum of three prime numbers .
Lets take an example,
- 3 + 3 + 5 = 11
- 3 + 5 + 5 = 13
- 5 + 5 + 7 = 17
Later on in 2013 the Mathematician <u>Harald Helfgott</u> proved this theory true for all odd numbers greater than five.
Answer:
a) A student travelling to school on public transport: 15/52 or 0.231
b) A student walking to school: 16/52 or 0.308
c) A student not cycling to school: 43/52 or 0.827
Step-by-step explanation:
Total people = 52
Travel Method Frequency
Public Transport 12
Car 15
Cycle 9
Walk 16
Find the relative frequency of.
The formula used will be: 
a) A student travelling to school on public transport:
Given Frequency: 12
Size of sample space: 52
Apply formula: 
Fraction = 12/52
Decimal = 0.231
b) A student walking to school
Given Frequency: 16
Size of sample space. 52
Apply formula: 
Fraction = 16/52
Decimal = 0.308
c) A student not cycling to school.
We will consider all students except those who cycle.
12+15+16 = 43
Given Frequency: 43
Size of sample space. 52
Apply formula: 
Fraction = 43/52
Decimal = 0.827
Answer:
answer it s 12. just put the value
Answer:
![12-[20-2(6^2\div3\times2^2)]=88](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D%3D88)
Step-by-step explanation:
So we have the expression:
![12-[20-2(6^2\div3\times2^2)]](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D)
Recall the order of operations or PEMDAS:
P: Operations within parentheses must be done first. On a side note, do parentheses before brackets.
E: Within the parentheses, if exponents are present, do them before all other operations.
M/D: Multiplication and division next, whichever comes first.
A/S: Addition and subtraction next, whichever comes first.
(Note: This is how the order of operations is traditionally taught and how it was to me. If this is different for you, I do apologize. However, the answer should be the same.)
Thus, we should do the operations inside the parentheses first. Therefore:
![12-[20-2(6^2\div3\times2^2)]](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D)
The parentheses is:

Square the 6 and the 4:

Do the operations from left to right. 36 divided by 3 is 12. 12 times 4 is 48:

Therefore, the original equation is now:
![12-[20-2(6^2\div3\times2^2)]\\=12- [20-2(48)]](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D%5C%5C%3D12-%20%5B20-2%2848%29%5D)
Multiply with the brackets:
![=12-[20-96]](https://tex.z-dn.net/?f=%3D12-%5B20-96%5D)
Subtract with the brackets:
![=12-[-76]](https://tex.z-dn.net/?f=%3D12-%5B-76%5D)
Two negatives make a positive. Add:

Therefore:
![12-[20-2(6^2\div3\times2^2)]=88](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D%3D88)