Answer: 50
Step-by-step explanation:
exterior angles are supplement of interior angle therefore the 110 thing must be 70, also youre given 60 so 70+60=130
50 is missing from 180
<span>The solution:
= 40, p = q = 0.5
P[x] = nCx *p^x *q^(n-x)
when p = q = 0.5, the formula simplifies to
P[x] = nCx/2^n = 40Cx/2^40
at least 18 of each type means 18 to 22 of (say) type I
P(18 <= X <= 22) = 0.5704095 <-------
qb
mean = 40*0.5 = 20
SD = sqrt(npq) = sqrt(40*0.5*0.5) = 3.1623
z1= (18-20)/3.1623 = -0.63 , z2 = (22-20)/3.1623 = 0.63
P(-0.63 < z < 0.63) = 0.4713 <-------</span>
Answer:
x = 40 in
Step-by-step explanation:
the missing angle in the triangle on the left is
180° - (74 + 51)° = 180° - 125° = 55°
the missing angle in the triangle on the right is
180° - (74 + 55)° = 180° - 129° = 51°
the 2 triangles have 3 pairs of congruent angles and are therefore congruent.
Corresponding sides and angles are then congruent
consider the corresponding sides opposite 74° , that is x and 40 in , so
x = 40 in
Answer:
40 = d+q
7.15=0.10d+0.25q
there are 19 dimes and 21 quarters.