Answer:
(3x-1)(2x+1)
Step-by-step explanation:
1-6x^2-x=0
-6x^2-x+1=0
6x^2+x-1=0
6x^2+(3-2)x-1=0
6x^2+3x-2x-1=0
3x(2x+1)-1(2x+1)=0
(3x-1)(2x+1)=0
So the factor is (3x-1)(2x+1)
Answer:
14 degrees
Step-by-step explanation:
12 + 25 - 23 = 14
Let’s call the speed of the slower car S, then the speed of the other is S+10mph.
At 5pm they have been travelling for 3 hours. The slower car travels a distance 3S and the faster one 3(S+10).
But the two distances must add up to 240 miles so 3S+3(S+10)=240, 3S+3S+30=240, 6S=210, S=35 mph. The faster car’s speed is 45mph. We can see that 3S is the same distance as 3x, so x=S=35 mph, and the distance the faster car travels is 3×45=135 miles.
Answer:
m∠P=140°
Step-by-step explanation:
Given:
∠P and ∠Q are supplementary angles.
The measure of angle P is five less than four times the measure of angle Q.
To find m∠P
Solution:
The measure of angle P can be given as:
A) 
And
B)
[Definition of supplementary angles]
Substituting equation A into B.

Solving for 
Using distribution:

Simplifying by combining like terms.

Adding 20 to both sides.


Dividing both sides by 5.


Substituting
in equation B.

Subtracting both sides by 40.


Thus, we have:
m∠P=140° (Answer)
Hello There!
Before we start, I am going to divide 3.5 by 2 because then we can multiply by 7 to see how far Jimmy can run in 70 minutes.
Jimmy can run 1.75 miles in 10 minutes.
To find out how many miles he can run in 70 minutes, we just multiply 1.75 by 7 and we get a product of 12.25
Jimmy Can Run 12.25 Miles In 70 Minutes