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3 years ago

Helllllllllllpppppppppppppppppp

Mathematics

1 answer:

leva [86]3 years ago

3 0

Answer: Negative 1 and one-fifth

Step-by-step explanation:

Add the two numbers lol

Hope this help

I'm a also a K12 kid too btw.

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A bowl of buttons contains 10 MAGA [MAKE AMERICA GREAT AGAIN] buttons, 5 GND [GREEN NEW DEAL] buttons and 10 NAW [NEVER A WALL]

kondaur [170]

Answer:

a) Probability of picking Two MAGA buttons without replacement = 0.15

b) Probability of picking a MAGA and GND button in that order = 0.0833

Probability of picking a MAGA and GND button in with the order unimportant = 0.167

Step-by-step explanation:

10 MAGA [MAKE AMERICA GREAT AGAIN] buttons, 5 GND [GREEN NEW DEAL] buttons and 10 NAW [NEVER A WALL] buttons.

Total number of buttons = 10 + 5 + 10 = 25

Let probability of picking a MAGA button be P(M) = 10/25 = 0.4

Probability of picking a GND button be P(G) = 5/25 = 0.2

Probability of picking a NAW button be P(N) = 10/25 = 0.4

a) Probability of picking Two MAGA buttons without replacement = (10/25) × (9/24) = 3/20 = 0.15

b) Probability of picking a MAGA and GND button in that order = (10/25) × (5/24) = 1/12 = 0.0833

Probability of picking a MAGA and GND button in with the order unimportant = [(10/25) × (5/24)] + [(5/25) × (10/24)] = 1/6 = 0.167

3 0

3 years ago

How can 1/5x − 2 = 1/3x + 8 be set up as a system of equations? a . 5y − 5x = −10. 3y − 3x = 24 b. 5y − 5x = −10. 3y + 3x = 24 c

VMariaS [17]

The answer is d. 5y − x = −10. 3y − x = 24

$\frac{1}{5}x-2= \frac{1}{3}x+8=y$
⇒    $y= \frac{1}{5}x-2$
   $y= \frac{1}{3}x+8$
________________________
$y= \frac{x}{5} -2= \frac{x}{5} - \frac{10}{5} = \frac{x-10}{5}$
$y= \frac{x}{3} +8= \frac{x}{3} + \frac{24}{3} = \frac{x+24}{3}$
________________________
$y= \frac{x-10}{5}$ ⇒    $5y=x-10$
$y= \frac{x+24}{3}$   ⇒    $3y=x+24$
________________________
$5y-x=-10$
$3y-x=24$

5 0

3 years ago

Dogs in the GoodDog Obedience School win a blue ribbon for learning how to sit, a green ribbon for learning how to roll over, an

Elan Coil [88]

There are 17 dogs who have not learned any tricks.

7 0

2 years ago

The population, P(t), of China, in billions, can be approximated by1 P(t)=1.394(1.006)t, where t is the number of years since th

vitfil [10]

Answer:

At the start of 2014, the population was growing at 8.34 million people per year.

At the start of 2015, the population was growing at 8.39 million people per year.

Step-by-step explanation:

To find how fast was the population growing at the start of 2014 and at the start of 2015 we need to take the derivative of the function with respect to t.

The derivative shows by how much the function (the population, in this case) is changing when the variable you're deriving with respect to (time) increases one unit (one year).

We know that the population, P(t), of China, in billions, can be approximated by $P(t)=1.394(1.006)^t$

To find the derivative you need to:

$\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=\\\\\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'\\\\1.394\frac{d}{dt}\left(1.006^t\right)\\\\\mathrm{Apply\:the\:derivative\:exponent\:rule}:\quad \frac{d}{dx}\left(a^x\right)=a^x\ln \left(a\right)\\\\1.394\cdot \:1.006^t\ln \left(1.006\right)\\\\\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=(1.394\cdot \ln \left(1.006\right))\cdot 1.006^t$

To find the population growing at the start of 2014 we say t = 0

$P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(0)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^0\\P(0)' = 0.00833901 \:Billion/year$

To find the population growing at the start of 2015 we say t = 1

$P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(1)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^1\\P(1)' = 0.00838904 \:Billion/year$

To convert billion to million you multiple by 1000

$P(0)' = 0.00833901 \:Billion/year \cdot 1000 = 8.34 \:Million/year \\P(1)' = 0.00838904 \:Billion/year \cdot 1000 = 8.39 \:Million/year$

6 0

2 years ago

Please help me. Should I know this?

slega [8]

you don't need to know this for real life situations but for school you do need to know it, i dont know how to do this but here's a link to the same question you have but it's explained on how to solve it

https://www.wyzant.com/resources/answers/499729/fireworks_can_go_up_to_1000_feet_in_around_3_seconds_what_s_is_it_s_average_vertical_speed_in_feet_per_second_and_miles_per_hour

((Also i'm a fellow ARMY as well =) ))

7 0

3 years ago