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Mashutka [201]
3 years ago
13

Evaluate :cos 45 by sin 30 + cosec 30​

Mathematics
2 answers:
barxatty [35]3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

Using the identity

cosecx = \frac{1}{sinx} and the exact values

cos45° = \frac{\sqrt{2} }{2}, sin30° = \frac{1}{2}

Given

cos45° × sin30° + cosec30°

= \frac{\sqrt{2} }{2} × \frac{1}{2} + \frac{1}{\frac{1}{2} }

= \frac{\sqrt{2} }{4} + 2

= \frac{\sqrt{2} }{4} + \frac{8}{4}

= \frac{1}{4}(\sqrt{2} + 8 ) ← exact value

≈2.354 ( 3 dec. places )

Yuliya22 [10]3 years ago
6 0

Answer:

\large\boxed{2+\sqrt2}\ or\ \boxed{\dfrac{8+\sqrt2}{4}}

Step-by-step explanation:

We know:

\csc\theta=\dfrac{1}{\sin\theta}

From the table (attachment):

\cos45^o=\dfrac{\sqrt2}{2}\\\\\sin30^o=\dfrac{1}{2}\\\\\csc30^o=\dfrac{1}{\sin30^o}=\dfrac{1}{\frac{1}{2}}=1\cdot\dfrac{2}{1}=2

Substitute:

If is:

\dfrac{\cos45^o}{\sin30^o}+\csc30^o=\dfrac{\frac{\sqrt2}{2}}{\frac{1}{2}}+2=\dfrac{\sqrt2}{2}\cdot\dfrac{2}{1}+2=\sqrt2+2

If is:

\cos45^o\cdot\sin30^o+\csc30^o=\dfrac{\sqrt2}{2}\cdot\dfrac{1}{2}+2=\dfrac{\sqrt2}{4}+2=\dfrac{\sqrt2}{4}+\dfrac{8}{4}=\dfrac{8+\sqrt2}{4}

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