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olga_2 [115]
3 years ago
10

9. Mohammed copied this problem into his notebook.

Mathematics
1 answer:
Mkey [24]3 years ago
8 0

Answer:

Its B

Step-by-step explanation:

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ANYONE PLEASE HELP ME WITH MY MATH HOMEWORK I REALLY NEED THE ANSWER RIGHT NOW BECAUSE I HAVE TO PASS THIS TOMORROW MORNING I HO
AleksAgata [21]

Answer:

A, C, E

Step-by-step explanation:

Associative

Commutative

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I think that it the correct answer!

Have a great day/night :)

8 0
3 years ago
Xy = 6<br> | 2x – y = 1<br> Solve each system by substitution
AnnZ [28]

Answer:  {x,y} = {2,-4}  

  [1]    x - y = 6

  [2]    2x + y = 0

Step-by-step explanation:

7 0
3 years ago
Use (a) the Trapezoidal Rule, (b) the Midpoint Rule, and (c) Simpson’s Rule to approximate the given integral
malfutka [58]

Answer:

10.294935

Step-by-step explanation:

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7 0
3 years ago
∠A and ​ ∠B ​ are vertical angles with m∠A=x and m∠B=3x−60 . What is m∠A ?
quester [9]
As they are vertical angles, their magnitude would be equal.
x = 3x - 60
3x - x = 60
2x = 60
 x= 30

In short, Your Answer would be 30

Hope this helps!
3 0
3 years ago
Prove or disprove that the point (√5, 12) is on the circle centered at the origin and containing the point (-13, 0). Show your w
pav-90 [236]

Using the equation of the circle, it is found that since it reaches an identity, the point (√5, 12) is on the circle.

<h3>What is the equation of a circle?</h3>

The equation of a circle of center (x_0, y_0) and radius r is given by:

(x - x_0)^2 + (y - y_0)^2 = r^2

In this problem, the circle is centered at the origin, hence (x_0, y_0) = (0,0).

The circle contains the point (-13,0), hence the radius is found as follows:

x^2 + y^2 = r^2

(-13)^2 + 0^2 = t^2

r^2 = 169

Hence the equation is:

x^2 + y^2 = 169

Then, we test if point (√5, 12) is on the circle:

x^2 + y^2 = 169

(\sqrt{5})^2 + 12^2 = 169

25 + 144 = 169

Which is an identity, hence point (√5, 12) is on the circle.

More can be learned about the equation of a circle at brainly.com/question/24307696

#SPJ1

6 0
2 years ago
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