Answer:
100%
Step-by-step explanation:
Use conditional probability:
P(B | A) = P(B and A) / P(A)
P(B | A) = (12/28) / P(A)
We need to find the probability that a student studies art.
P(A or B) = P(A) + P(B) − P(A and B)
24/28 = P(A) + (12+12)/28 − 12/28
P(A) = 12/28
P(B | A) = (12/28) / (12/28)
P(B | A) = 1
What this means is that all of the students who study art also study biology.
The area of the garden is 120 square metre
<h2>
Explanation:</h2>
The picture of the garden is shown below. In this problem, we have:
Recall that the area of a square is given by:
![A_{s}=L^2 \\ \\ A_{s}:Area \ of \ a \ square \\ L:Side \ of \ the \ square](https://tex.z-dn.net/?f=A_%7Bs%7D%3DL%5E2%20%5C%5C%20%5C%5C%20A_%7Bs%7D%3AArea%20%5C%20of%20%5C%20a%20%5C%20square%20%5C%5C%20L%3ASide%20%5C%20of%20%5C%20the%20%5C%20square)
On the other hand, the area of a rectangle is given by:
![A_{r}=L_{1}\times L_{2} \\ \\ \\ A_{r}:Area \ of \ a \ rectangle \\ \\ L_{1}:Side \ 1 \ of \ the \ rectangle \\ \\ L_{2}:Side \ 2 \ of \ the \ rectangle](https://tex.z-dn.net/?f=A_%7Br%7D%3DL_%7B1%7D%5Ctimes%20L_%7B2%7D%20%5C%5C%20%5C%5C%20%5C%5C%20A_%7Br%7D%3AArea%20%5C%20of%20%5C%20a%20%5C%20rectangle%20%5C%5C%20%5C%5C%20L_%7B1%7D%3ASide%20%5C%201%20%5C%20of%20%5C%20the%20%5C%20rectangle%20%5C%5C%20%5C%5C%20L_%7B2%7D%3ASide%20%5C%202%20%5C%20of%20%5C%20the%20%5C%20rectangle)
Therefore:
FOR THE SQUARE:
![L=4m \\ \\ \\ Substituting \ values: \\ \\ \\ A_{s}=4^2 \\ \\ \boxed{A_{s}=16m^2}](https://tex.z-dn.net/?f=L%3D4m%20%5C%5C%20%5C%5C%20%5C%5C%20Substituting%20%5C%20values%3A%20%5C%5C%20%5C%5C%20%5C%5C%20A_%7Bs%7D%3D4%5E2%20%5C%5C%20%5C%5C%20%5Cboxed%7BA_%7Bs%7D%3D16m%5E2%7D)
FOR THE RECTANGLE 1:
![L_{1}=6m \\ L_{2}=4m \\ \\ \\ Substituting \ values: \\ \\ \\ A_{r_{1}}=6(4) \\ \\ \boxed{A_{r_{1}}=24m^2}](https://tex.z-dn.net/?f=L_%7B1%7D%3D6m%20%5C%5C%20L_%7B2%7D%3D4m%20%5C%5C%20%5C%5C%20%5C%5C%20Substituting%20%5C%20values%3A%20%5C%5C%20%5C%5C%20%5C%5C%20A_%7Br_%7B1%7D%7D%3D6%284%29%20%5C%5C%20%5C%5C%20%5Cboxed%7BA_%7Br_%7B1%7D%7D%3D24m%5E2%7D)
FOR THE RECTANGLE 2:
![L_{1}=10m \\ L_{2}=8m \\ \\ \\ Substituting \ values: \\ \\ \\ A_{r_{2}}=10(8) \\ \\ \boxed{A_{r_{2}}=80m^2}](https://tex.z-dn.net/?f=L_%7B1%7D%3D10m%20%5C%5C%20L_%7B2%7D%3D8m%20%5C%5C%20%5C%5C%20%5C%5C%20Substituting%20%5C%20values%3A%20%5C%5C%20%5C%5C%20%5C%5C%20A_%7Br_%7B2%7D%7D%3D10%288%29%20%5C%5C%20%5C%5C%20%5Cboxed%7BA_%7Br_%7B2%7D%7D%3D80m%5E2%7D)
Finally, the area of a garden is the sum of the three areas:
![A_{total}=A_{s}+A_{r_{1}}+A_{r_{2}} \\ \\ A_{total}=16m^2+24m^2+80m^2 \\ \\ A_{total}=16+24+80 \\ \\ \boxed{A_{total}=120m^2}](https://tex.z-dn.net/?f=A_%7Btotal%7D%3DA_%7Bs%7D%2BA_%7Br_%7B1%7D%7D%2BA_%7Br_%7B2%7D%7D%20%5C%5C%20%5C%5C%20A_%7Btotal%7D%3D16m%5E2%2B24m%5E2%2B80m%5E2%20%5C%5C%20%5C%5C%20A_%7Btotal%7D%3D16%2B24%2B80%20%5C%5C%20%5C%5C%20%5Cboxed%7BA_%7Btotal%7D%3D120m%5E2%7D)
<h2>Learn more:</h2>
Area of a pizza: brainly.com/question/12878495
#LearnWithBrainly
Answer: 48.54101966249685
Step-by-step explanation:
Answer:
4y^6
Step-by-step explanation:
Take out the constants:
40y^14/10y^8
= 40/10 * y^14 / y^8
= 4 * y^(14-8)
= 4 * y^6
= 4y^6
Hope this helped you :3
First, we must let:
x = number of tickets intended for adults
y = number of tickets intended for children.
a. Write in terms of x the number of tickets for children
Solution:
x + y = 28 ⇔ y = 28 - x (equation 1)
To answer in terms of x:
no. of tickets for tickets for children = 28 - x
b. the amount spent on tickets for adults
Solution: $30 is the cost of ticket per adult and there are x number of tickets intended for adults.
Therefore,
amount spent on ticket for adults = 30x
c. the amount spent on the tickets.
Solution:
$ 15 = cost of ticket per child
$ 30 = cost of ticket per adult
total amount spent on tickets = 30x + 15y ⇒ (equation2)
substitute equation 1 to equation 2.
(equation 1) y = 28 - x
(equation 2) total amount spent on tickets = 30x + 15y
total amount spent on tickets = 30x + 15(28-x)
total amount spent on tickets = 30x + 420 - 15x
total amount spent on tickets = 15x + 420